x + 2y + 3 = 0
Subtract x from both sides.
2y + 3 = -x
Subtract 3 from both sides.
2y = -x - 3
Divide by 2 on both sides
y = -(x+3)/2
x + y + 4 = 0
Subtract x and 4 from both sides
y = -x - 4
3x - 2y + 4 = 0
Subtract 3x and 4 from both sides.
-2y = -3x -4
Divide by -2 from both sides.
y = -(3x + 4) / 2
The answer is the graph that contains these slopes and lines on the graph, which was not provided.
6^3 = 216. When using chance, take the number of outcomes(six for a die) and raise it to the power of the number of repetitions
The correct answer for the question that is being presented above is this one:
We want to pull 11 (this means not including 12) or less from the bag and there are 100 possibilities
= 11/100
So the probability is <span>11/100</span>
Step-by-step explanation:
f(x) = x² + 1, where x >= 0.
Let y be f(x).
=> y = x² + 1
=> x² = y - 1
=> x = √(y - 1) because x is non-negative.
Hence f^-1(x) = √(x - 1), where x >= 1.
since by the provided tickmarks WE ≅ ER, and QE ≅ ET, then both triangles are congruent by LL theorem, Leg Leg.
anyhow, since those legs are congruent, their hypotenuses must also be congruents, and we could use the HL theorem as well.