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aliya0001 [1]
3 years ago
14

The 2 triangles shown in the figure are similar. Find the distance "d" across the Red River

Mathematics
1 answer:
Aliun [14]3 years ago
6 0
2 km... Since 1.8 is 2(.9), you do the same for the base of the smaller triangle (just multiply by two)
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Find the difference. (7x-6 2/3) - (-3x + 4 3/4)
NikAS [45]

10x-61/12 is the difference of  (7x-6\frac{2}{3}) - (-3x + 4\frac{3}{4}).

<h3>What is Expression?</h3>

An expression is combination of variables, numbers and operators.

The given expression is (7x-6\frac{2}{3}) - (-3x + 4\frac{3}{4})

7x-6\frac{2}{3}+3x- 4\frac{3}{4}

7x-20/3+3x-19/4

Add the variable terms and constant terms.

10x-20/3-19/4

The LCM of 3 and 4 is 12/

10x-4-57/12

10x-61/12

Hence, 10x-61/12 is the difference of  (7x-6\frac{2}{3}) - (-3x + 4\frac{3}{4}).

To learn more on Expressions click:

brainly.com/question/14083225

#SPJ1

4 0
1 year ago
YES OR NOOO PLEASEE ANSWER
dlinn [17]

Answer:

Not a Function.... hope you pass!

7 0
2 years ago
Factor the trinomial 2x^2+15x+7
Mashutka [201]

Answer:

(2x+1)(x+7)

Step-by-step explanation:

2x2+15x+7

For a polynomial of the form ax2+bx+c

, rewrite the middle term as a sum of two terms whose product is a⋅c=2⋅7=14 and whose sum is b=15

.

Tap for more steps...

2x2+x+14x+7

Factor out the greatest common factor from each group.

Tap for more steps...

x(2x+1)+7(2x+1)

Factor the polynomial by factoring out the greatest common factor, 2x+1

.

(2x+1)(x+7)

3 0
2 years ago
Which is the factored form of 3y -18
Eva8 [605]
The only things you can factor out of here is a 3 so you are left with:

3(y-6)

Hope that helps.
5 0
3 years ago
Pi/6 is the reference angle for:<br><br> 3pi/6<br><br> 5pi/6<br><br> 13pi/6<br><br> 8pi/6
Elanso [62]

Answer:

\frac{5\pi}{6}, \frac{13\pi}{6}

Step by step

Remember, a reference angle is a positive acute angle that represents an angle θ of any measurement.

a)

\frac{3\pi}{6}=90^\circ, then its reference angle is \frac{\pi}{2}

b)

\frac{5\pi}{6}=150^ \circ is in the second cuadrant, then its reference angle is 180^ \circ -150^{\circ}=30^{\circ}=\frac{\pi}{6}

c)

\frac{13\pi}{6}=390^\circ=360^\circ+30^\circ, then it is in the first cuadrant and the reference angle is 30^\circ =\frac{\pi}{6}.

d)

\frac{8\pi}{6}=240^\circ and it is in the third cuadrant, then its reference angle is 240^\circ -180^\circ=60^\circ=\frac{\pi}{3}

5 0
3 years ago
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