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Stels [109]
3 years ago
11

What is negative 8 to the fifth power?

Mathematics
1 answer:
Sliva [168]3 years ago
4 0
I think the answer is -32768
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If p(a) = 0.62, p(b) = 0.47, and p(a or<br> b.= 0.88, then p(a and<br> b.= _____
SIZIF [17.4K]
Use the identity:
P(A or B)=P(A)+P(B)-P(A and B)
Substitute given values,
0.88=0.62+0.47-P(A and B)
=>
P(A and B)=0.62+0.47-0.88=0.21
6 0
4 years ago
Which descsription means the same as this limit expression?
Nady [450]

Answer:

Step-by-step explanation:

a

6 0
3 years ago
How many quarts are in 1200 fl oz?
Semenov [28]

Answer:

37 1/2

Step-by-step explanation:

hope this helps:)

5 0
3 years ago
Read 2 more answers
A coin is flipped, and a number cube is rolled. What is the probability of getting heads on the coin and a number less than 3 on
nata0808 [166]
<h3>Answer:  one sixth (choice B)</h3>

=============================================================

Explanation:

The probability of getting heads is 1/2 because there's one side we want out of two sides total

The probability of getting less than 3 is 2/6 = 1/3 since we have two sides we want (rolling a "1" or a "2") out of six sides total.

Multiply the two mentioned fractions: 1/2 times 1/3 = 1/6

1/6 can be written as "one sixth", but I prefer the first format better since it's shorter.

---------------

If you are a visual learner, you can make a table with 2 rows and 6 columns, or vice versa (6 rows and 2 columns). The order doesn't matter.

The two rows represent the events Heads or Tails. The 6 columns show the different outcomes on the number cube. We have 6*2 = 12 different outcomes of rolling a die and flipping a coin.

Of those 12 outcomes, shade in 2 boxes to represent getting heads and either a "1" or "2". Refer to the diagram below.

We have 2 shaded rectangles out of 12 total to get 2/12 = 1/6

The visual representation of a table like this may help show why we multiplied the fractions 1/2 and 1/3 to get the answer. Hint: think of area = length*width.

8 0
2 years ago
Which of the following inequalities is not true? |-9| ≠ |9| -2 ^2 &lt; 3 -7 ≤ -5 |-1| ≥ 0
guajiro [1.7K]

Answer:

(a) |-9| ≠ |9| is NOT TRUE.

(b) -2 ^2< 3   is TRUE

(c)  -7 ≤ -5 is TRUE

(d) |-1| ≥ 0 is TRUE.

Step-by-step explanation:

Solving each expression separably:

(a)  |-9| ≠ |9|

By the definition of <u>MODULUS FUNCTION</u>:  IxI = x, if x > 0

                                                                              = (-x) if x <, 0

⇒ I-9I = -(-9)  = 9, and I9I = 9

So, I-9I = I9I . Hence, |-9| ≠ |9| is NOT TRUE.

(b) -2 ^2< 3  

⇒-2 ^2 = (-2) \times (-2) \times (-2)  = -8  

and (-8) < 3.

Hence,  -2 ^2< 3   is TRUE

(c) -7 ≤ -5

-7 < -5  on the number line of integers.

Hence, -7 ≤ -5 is TRUE

(d) |-1| ≥ 0

I(-1)I  = -(-1)  = 1

and 1 > 0

Hence, |-1| ≥ 0 is TRUE.

6 0
3 years ago
Read 2 more answers
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