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3 years ago

Can you answer this problem?

Mathematics

1 answer:

Rasek [7]3 years ago

4 0

When there is a negative in squre root, it means imaginary number come in. 'i' is usually the varible used to identify imaginary numbers.
First remove the negative from the square root and find the square root of 4, which is 2. Then add i to 2. 2i

Now solve for the positive then negative.

-2 + 2i
----------- = -1 + 1i
2

-2 - 2i
----------- = -1 - 1i
2

Both -1 + 1i and -1 - 1i are the answers.

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Greg drew a scale drawing of a house. The hall closet is 2 inches wide in the drawing. The actual closet is 6 feet wide. What is

Vlad [161]

The drawing's scale factor is
Actual Dimensions:Drawing Measurements
= 36:1

4 0

4 years ago

Please help me with 2b ASAP. <br> Really appreciate it!!

Bogdan [553]

$f(x)=\dfrac{x^2}{x^2+k^2}$

By definition of the derivative,

$f'(x)=\displaystyle\lim_{h\to0}\frac{\frac{(x+h)^2}{(x+h)^2+k^2}-\frac{x^2}{x^2+k^2}}h$

$f'(x)=\displaystyle\lim_{h\to0}\frac{(x+h)^2(x^2+k^2)-x^2((x+h)^2+k^2)}{h(x^2+k^2)((x+h)^2+k^2)}$

$f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{(x+h)^2-x^2}{h((x+h)^2+k^2)}$

$f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{2xh+h^2}{h((x+h)^2+k^2)}$

$f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{2x+h}{(x+h)^2+k^2}$

$f'(x)=\dfrac{2xk^2}{(x^2+k^2)^2}$

$\dfrac{k^2}{(x^2+k^2)^2}$ is positive for all values of $x$ and $k$ . As pointed out, $x\ge0$ , so $f'(x)\ge0$ for all $x\ge0$ . This means the proportion of occupied binding sites is an increasing function of the concentration of oxygen, meaning the presence of more oxygen is consistent with greater availability of binding sites. (The question says as much in the second sentence.)

7 0

3 years ago

Question 1.:

klasskru [66]

Answer:

-7 is bigger

-9 is bigger

-6 is bigger

7 is bigger

I think.....

-9,-8,-7,-6,-4

-9,-7,-6,4,7

-2-1,0,4,9

-8,-2,3,5,8 ?

I guess I didn't understand the question

8 0

3 years ago

Evaluate k(x) = -k - 7 when k(-4)

FinnZ [79.3K]

Answer:

I'm not sure but i think that it's

x= -7

Hope this helps

8 0

3 years ago

Lamar is solving the equation x2−12x=−6 by completing the square. Which shows Lamar's next step and the solution to the equation

Levart [38]

Completing the square is a process to find the solutions, or the x-values, to a quadratic equation. This method can only work if it is in the format: x^2 + bx = c
In this equation, the b value is -12 and the c value is -6. The process for completing the square goes like this:

x^2 + bx + (b/2)^2 = c + (b/2)^2

Now let’s solve the equation above using this method.

Step 1: x^2 - 12x + (-12/2)^2 = -6 + (-12/2)^2

Step 2: x^2 - 12x + (-6)^2 = -6 + (-6)^2

Step 3: x^2 - 12x + 36 = -6 + 36

Step 4: x^2 - 12x + 36 = 30

Now, to factor it. After doing the process until now, the left side of the equation can ALWAYS be in the format: (x + a)^2

Step 5: x^2 - 12x + 36 can be factored in this format as (x - 6)^2

Step 6: (x - 6)^2 = 30

Step 7: x - 6 = √30

Step 8: x = 6 ±√30

4 0

2 years ago