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alexgriva [62]
3 years ago
8

Can you answer this problem?

Mathematics
1 answer:
Rasek [7]3 years ago
4 0
When there is a negative in squre root, it means imaginary number come in. 'i' is usually the varible used to identify imaginary numbers.
First remove the negative from the square root and find the square root of 4, which is 2. Then add i to 2. 2i

Now solve for the positive then negative.

-2 + 2i
----------- = -1 + 1i
2

-2 - 2i
----------- = -1 - 1i
2

Both -1 + 1i and -1 - 1i are the answers.
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Tanya has several different ways she likes to walk home. One route takes 20 minutes, two of the routes take 30 minutes, and two
stira [4]
50% because there are 4 routes and 2 take 30 minutes, 2/4 = 50/100 = 50%
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it takes josh 40 minutes yo walk the dog it takes mike 80% as long to walk the dog how long does it take mike to walk dog
Katarina [22]

Answer:

32 minutes

Step-by-step explanation:

80% = .80

40 * .80 = 32

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Paulo works at the United Nations. He researched what percent of the world's population lives on each continent. He surveys a sa
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Answer:

confidence interval using a  two sample t test between percents

Step-by-step explanation:

confidence interval using a  two sample t test between percents This can be used to compare percentages drawn from two independent samples in this case employees. It is used to compare two sub groups from a single sample example the population on the planet

5 0
3 years ago
Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ​ ,0)(, plus minus, square root o
Alchen [17]

Answer:

The equation of ellipse centered at the origin

\frac{x^2}{18} +\frac{y^2}{10} =1

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)  

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are c^2=a^2-b^2

      a^{2} = c^{2} +b^{2}

a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}

a^{2} =18

a=\sqrt{18}

The equation of ellipse formula

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

we know that a=\sqrt{18} and b=\sqrt{10}

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u />\frac{x^2}{18} +\frac{y^2}{10} =1<u />

                                   

8 0
3 years ago
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When finding the 9th term in a geometric sequence with a common ratio of 2 and a first
Zarrin [17]

Answer:

8

Step-by-step explanation:

Nth term of a geometric sequence is given as:

t_n = a r^{(n-1)} ...(1)

Plugging n = 9, a = 3 and r = 2 in the above equation, we find:

t_9 = (3) (2)^{9-1}

t_9 = (3) (2)^{8}... (2)

Comparing equations (1) & (2), we obtan:

(n - 1) = 8

5 0
3 years ago
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