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3 years ago

10

In a newspaper, it was reported that yearly robberies in Springfield were up 50% to 93 in 2013 from 2012. How many robberies wer

e there in Springfield in 2012?

2 answers:

DiKsa [7]3 years ago

8 0

Answer:

There were 62 deaths

Step-by-step explanation:

In this question, we are asked to calculate the number of robberies in 2012.

From the question we can identify that the number of robberies were up 50% to 93. What this means is that the number is simply 150% of the old number.

Now, let’s represent the number of deaths in 2012 by x

Mathematically;

150% of x = 93

150/100 * x = 93

150x = 93 * 100

150x = 9300

x = 9300/150

x= 62

This means there were 62 deaths in the year 2012

Orlov [11]3 years ago

7 0

Answer:

There were 62 robberies in Springfield in 2012.

Step-by-step explanation:

Let's marked (named) robberies in 2012 with x, which is worth 100%

93 robberies in 2013 worth 100% + 50% = 150%

Now we will make proportion

x : 93 = 100 : 150

When we multiply external and internal members we get

x/93 = 100/150

Cross multiply

150 x = 93 × 100

150x = 9300

x = 9300/150

x = 62 robberies in 2012

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miskamm [114]

Answer:

45.24m

Step-by-step explanation:

Area of square = s^2

128 = s^2

s^2 = 11.31m.

This is the length of ONE SIDE.

Squares have four sides.

Homeboy wants to place a fence bordering is entire yard. AKA four sides.

11.31*4= 45.24m

7 0

3 years ago

Hello, may I please have some help on these 4 questions? Thanks very much! {Also, if you could answer them quick, that would be

wlad13 [49]

1.

Parallelogram with base a = 20 in. and height h = 16 in.
Triangle with base a = 20 in. and height b = 8 in.

so:

$A = A_P+A_T=a\cdot h+\frac{1}{2}\cdot a\cdot b=20\cdot16+\frac{1}{2}\cdot20\cdot8=320+80=\\\\=\boxed{400\text{ in}^2}$

2.

Trapezoid with base b₁ = 14 cm, base b₂ = 4 cm and height h = 10 cm
Triangle with base b₁ = 14 cm and height x = 18 cm - 10 cm = 8 cm

so:

$A=A_T+A_\Delta=\frac{1}{2}\cdot(b_1+b_2)\cdot h+\frac{1}{2}\cdot b_1\cdot x=\\\\=
\frac{1}{2}\cdot(14+4)\cdot 10+\frac{1}{2}\cdot 14\cdot8=\frac{1}{2}\cdot18\cdot 10+\frac{1}{2}\cdot 14\cdot8=90+56=\\\\=\boxed{146\text{ cm}^2}$

3.

We have three rectangles:

$A=A_1+A_2+A_3=1\cdot 4+6\cdot5+18\cdot6=4+30+108=\boxed{142\text{ ft}^2}$

4.

Area of a circle:

$A_\circ=\pi\cdot r^2=3.14\cdot5^2=3.14\cdot25=78.5 \text{ cm}^2$

Area of a rectangle:

$A_R=8\cdot 6=48\text{ cm}^2$

Area of the shaded region:

$A=A_\circ-A_R=78.5-48=\boxed{30.5\text{ cm}^2}$

3 0

3 years ago

Help me on calculating the area of the shaded part

Ymorist [56]

Answer:

$1051 .55 {mm}^{2}$

Step-by-step explanation:

Find the area of the square - area of 4 sectors

We'll use the formula to find one sector area

$a = \frac{1}{2} \times {r}^{2} \times x$

where r is the radius of one sector and x is the angle in radians

Since each angle is in a square, the angle of the sectors is 90 degrees.

Convert degrees to radians

$90 = \frac{1}{2} \pi \: rad$

The radius of one sector is given by 70mm/2=35mm

One sector area:

$\frac{1}{2} \times {35}^{2} \times \frac{1}{2} \pi = 306.25\pi$

Area of all 4 sectors:

$4 \times 306.25\pi = 1225\pi$

Area of the square:

$70 \times 70 = 4900$

Hence, Area of square - 4 Sectors:

$4900 - 1225\pi = 1051.55 {mm}^{2} (2dp)$

6 0

2 years ago

Read 2 more answers

Solve the following equation for x. Round the answer to the nearest hundredth.

Serhud [2]

Hence, option D 4: x=-1.34 is correct

Further explanation:

In order to solve an equation in one varible we have to isolate the variable on one side of the equations

Given equation is:

$-1.2x=2(x+2.15)\\Simplifying\\-1.2x=2x+4.3\\Subtracting\ 2x\ from\ both\ sides\\-1.2x-2x=2x+4.3-2x\\-3.2x=4.3\\Dividing\ both\ sides\ by\ -3.2\\\frac{-3.2x}{-3.2}=\frac{4.3}{-3.2}\\x=-1.34375\\Rounding\ off\ to\ nearest\ 100th\\x=-1.34$

Hence, option D: x=-1.34 is correct

Keywords: Linear equation in one variable, Solution of equation

Learn more about Linear equations at:

#LearnwithBrainly

5 0

3 years ago

Suppose that 76% of Americans prefer Coke to Pepsi. A sample of 80 was taken. What is the probability that at least seventy perc

Anastasy [175]

Answer:

C. 0.896

Step-by-step explanation:

We use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 80, p = 0.76$

So

$E(X) = np = 80*0.76 = 60.8$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{80*0.76*0.24} = 3.82$

What is the probability that at least seventy percent of the sample prefers Coke to Pepsi?

0.7*80 = 56.

This probability is 1 subtracted by the pvalue of Z when X = 56. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{56 - 60.8}{3.82}$

$Z = -1.26$

$Z = -1.26$ has a pvalue of 0.1040.

1 - 0.1040 = 0.8960

So the correct answer is:

C. 0.896

4 0

3 years ago