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Softa [21]
3 years ago
14

Evaluate P(3, 0). 0 1 6

Mathematics
2 answers:
arsen [322]3 years ago
7 0
_{3}P_{0} = \frac{3!}{(3 - 0)!}
_{3}P_{0} = \frac{3!}{3!}
_{3}P_{0} = \frac{3 * 2 * 1}{3 * 2 * 1}
_{3}P_{0} = 1

The answer is B.
VashaNatasha [74]3 years ago
4 0

Answer:

Option B. 1

Step-by-step explanation:

We have to find the value of P(3, 0)

We have to find the value of given permutation ^{3}P_{0}

Since we know ^{a}P_{b}=\frac{a!}{(a-b)!}

Here a = 3

b = 0

^{3}P_{0}=\frac{3!}{(3-0)!}

=\frac{3!}{3!}=1

Therefore, option B. 1 is the answer.

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