Evaluate P(3, 0). 0 1 6

2 answers:

7 0

$_{3}P_{0} = \frac{3!}{(3 - 0)!}$
$_{3}P_{0} = \frac{3!}{3!}$
$_{3}P_{0} = \frac{3 * 2 * 1}{3 * 2 * 1}$
$_{3}P_{0} = 1$

The answer is B.

VashaNatasha [74]3 years ago

4 0

Answer:

Option B. 1

Step-by-step explanation:

We have to find the value of P(3, 0)

We have to find the value of given permutation $^{3}P_{0}$

Since we know $^{a}P_{b}=\frac{a!}{(a-b)!}$

Here a = 3

b = 0

$^{3}P_{0}=\frac{3!}{(3-0)!}$

$=\frac{3!}{3!}=1$

Therefore, option B. 1 is the answer.

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