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andreyandreev [35.5K]
3 years ago
7

Suppose you roll a number cube and flip a coin/

Mathematics
1 answer:
blondinia [14]3 years ago
4 0
A Independent because they are two separate events<span />
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Scale factor from A to B is 4:5.<br> Help
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The missing value is 24
you can solve this by dividing 30 by 5 (6) and then multiplying that by 4
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A triangle has side lengths 5 miles in 13 miles is it a right triangle
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jgfshd

Step-by-step explanation:

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What is the value of the expression 8.3 × 104 − 2.5 × 103 − 1.9 × 104 written in scientific notation?
bezimeni [28]
Remark work with the two numbers that are 10^4 first. Then add in the one that goes to 10^3

Method one
You could change these all to integers and then take it back to scientific notation.

 83 000
<u>-19 000</u>
  64 000
<u>-   2 500
</u>  61 500 <u /><<<<<< answer

Method two
Keep the scientific notation.
 8.3 * 10^4
<u>-1.9 * 10^4</u>
 6.4 * 10^4
<u>-  .25*10^4</u>  Note the powers of ten must be the same.
  6.15*10^4 <<<<<<<< answer
<u>
</u>Either method works. 
<u>
</u>You could use your calculator to get the right answer. I'm not sure all calculators retain the scientific notation. Test yours to see what it does. Enter 8.3*10y^x 4 *1 = 
<u>
</u>Your calculator might have x^y or ^ to record powers. You may also have EE and one of your keys.
<u>
</u>See if your calculator returns 8.3*10^4 or if it returns 83000<u>
</u>
4 0
3 years ago
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What expression is equivalent to ^3 square root of 2y^3 times 7 square root of 18y
Mumz [18]

Answer:

\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})

Step-by-step explanation:

The question is poorly formatted.

Given

\sqrt[3]{2y^3} * 7\sqrt{18y}

Required

Derive an equivalent expression

\sqrt[3]{2y^3} * 7\sqrt{18y}

Express 18 as 9 * 2

\sqrt[3]{2y^3} * 7\sqrt{9 * 2y}

Split the expression as follows:

\sqrt[3]{2y^3} * 7\sqrt{9} * \sqrt{2y}

Take positive square root of 9

\sqrt[3]{2y^3} * 7*3 * \sqrt{2y}

\sqrt[3]{2y^3} * 21 * \sqrt{2y}

21*\sqrt[3]{2y^3} *  \sqrt{2y}

The cube root can be rewritten to give:

21*\sqrt[3]{2}*\sqrt[3]{y^3} *  \sqrt{2y}

\sqrt[3]{y^3} = y^{3*\frac{1}{3}} = y

So, we have:

21*\sqrt[3]{2} * y *  \sqrt{2y}

Rewrite as:

21y *\sqrt[3]{2}  *  \sqrt{2y}

Split \sqrt{2y

21y *\sqrt[3]{2}  *  \sqrt{2} * \sqrt{y}

Collect Like Terms

21y*\sqrt{y} *\sqrt[3]{2}  *  \sqrt{2}

Represent in index form

21y*y^{\frac{1}{2}} *2^\frac{1}{3} *2^\frac{1}{2}

Apply law of indices

21*y^{1+\frac{1}{2}} *2^{\frac{1}{3} +\frac{1}{2} }

21*y^{\frac{2+1}{2}} *2^{\frac{2+3}{6}}

21*y^{\frac{3}{2}} *2^{\frac{5}{6}}

21(y^{\frac{3}{2}})(2^{\frac{5}{6}})

Hence:

\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})

6 0
3 years ago
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