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enyata [817]
3 years ago
10

If f(x) = 72(1.25)^x and f(1) = 72(1.25)^1 = 11.25 f(2) = 72(1.25)^2 = ?????????

Mathematics
1 answer:
KengaRu [80]3 years ago
6 0

Answer:

f(1)=101.25 and f(2)=112.5

Step-by-step explanation:

f(1) = 72(1.25)^1 = 11.25

f(1)=90=11.25

f(1)=101.25

f(2) = 72(1.25)^2

f(2)=72(1.5625)

f(2)=112.5

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Answer:

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Step-by-step explanation:

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5 0
3 years ago
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svet-max [94.6K]

Answer:

$285

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Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 502, \sigma = 115

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

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Z = \frac{X - \mu}{\sigma}

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Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

#SPJ1

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