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3 years ago

13 is the same as 1÷3. What is the exact quotient in decimal form of 1÷3?

2 answers:

meriva3 years ago

4 0

13 is not the same as 1/3! The division symbol is not a symbol used to connect two numbers, it is used to find their quotient. For example, 6/2 would be like saying: You have 6 cookies, and 2 friends. How many cookies does each friend get? The answer is obviously not 62, it is 3! So, the exact quotient is 0.3 repeating. You could memorize this or use the fact that 0.9 repeating is 1.

wariber [46]3 years ago

3 0

Answer:

There is not an exact number, but an approximate one for: $\frac{1}{3}=0.\bar{3}=0.3333....\approx0.3$

Step-by-step explanation:

(Supposing that 13 on the text means $\frac{1}{3}$ )

$\frac{1}{3}$ <em>is the same as 1÷3.What is the exact quotient in decimal form of 1÷3?</em>

Since the quotient of $\frac{1}{3}$ is a repeating (not terminating) decimal, there is no exact quotient but an approximate number:

$\frac{1}{3}=0.\bar{3}=0.3333....\approx0.3$

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3 years ago

A pharmaceutical company receives large shipments of ibuprofen tablets and uses an acceptance sampling plan. This plan randomly

Keith_Richards [23]

Answer:

0.7208 = 72.08% probability that this whole shipment will be accepted.

Step-by-step explanation:

For each tablet, there are only two possible outcomes. Either it meets the required specifications, or it does not. The probability of a tablet meeting the required specifications is independent of any other tablet, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

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And p is the probability of X happening.

4% rate of defects

This means that $p = 0.04$

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This means that $n = 26$

What is the probability that this whole shipment will be accepted?

Probability that at most one tablet does not meet the specifications, which is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

Thus

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{26,0}.(0.04)^{0}.(0.96)^{26} = 0.3460$

$P(X = 1) = C_{26,1}.(0.04)^{1}.(0.96)^{25} = 0.3748$

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0.7208 = 72.08% probability that this whole shipment will be accepted.

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3 years ago

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Answer:

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