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Darya [45]
3 years ago
15

Sodium has an atomic number of 11 and has a net charge of 0. When sodium combines with chlorine, it has a net charge of +1. Why?

Chemistry
2 answers:
lianna [129]3 years ago
8 0

Sodium loses a negative electron when forming chemical bonds. When it loses an electron, it becomes a sodium ion with a net charge of +1.


Lena [83]3 years ago
5 0
It has to be noted that sodium is an element which belongs in the first column of the periodic table. This means that it has  a valence electron of 1 which further means that it is capable of donating one of its electron to another element during reaction. This is exactly the explanation as to why it becomes charged +1 after the reaction. 
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marysya [2.9K]
The eight-element periodicity found in the Periodic Table is related to the number of electrons in the outermost energy level of the atoms that make up each element 
this statement is true
3 0
3 years ago
What can be added to an atom to cause a nonvalence electron in the atom to temporarily become a valence electron?
vazorg [7]

Answer:

<em>What can be added to an atom to cause a nonvalence electron in the atom to temporarily become a valence electron </em>is<u><em> energy</em></u><em>.</em>

Explanation:

The normal state of the atoms, where all the electrons are occupying the lowest possible energy level, is called ground state.

The <em>valence electrons</em> are the electrons that occupy the outermost shell, this is the electrons in the highest main energy level (principal quantum number) of the atom.

So, a <em>nonvalence electron</em> occupies an orbital with less energy than what a valence electron does; in consequence, in order to a nonvalence electron jump from its lower energy level to the higher energy level of a valence electron, the former has to absorb (gain) energy.

This new state is called excited state and is temporary: the electron promoted to the higher energy level will emit the excess energy, in the form of light (photons), to come back to the lower energy level and so the atom return to the ground state.

6 0
4 years ago
Read 2 more answers
In the lab, you added an excess of acetic acid to drive the reaction forward, favoring products at equilibrium according to Le C
AysviL [449]

Answer:

Remove exess water

Explanation:

The reaction involved is an esterification reaction. Esterification is a reaction in which alcohol and carboxylic acid reacts to yield an ester and water. It is analogous to the inorganic neutralization reaction.

According to Le Chatelier's principle , one method of driving the equilibrium towards the forward reaction is by removal of one of the products. In this case, if water is removed, the forward reaction is favoured.

6 0
4 years ago
A NaOH solution is standardized using the monoprotic primary standard potassium hydrogen phthalate, KHP (204.22 g/mol.) If 0.698
kakasveta [241]

Answer:

0.07789 M is the sodium hydroxide concentration.

Explanation:

Mass of potassium hydrogen phthalate = 0.6986 g

Molar mass of potassium hydrogen phthalate = 204.22 g/mol

Moles of  potassium hydrogen phthalate = \frac{0.6986 g}{204.22 g/mol}=0.003421 mol

NaOH+KHP\rightarrow NaKP+H_2O

According to reaction , 1 mole og KHp reactswith 1 mole of NaOH , then 0.003421 moles of KHp will react with :

\frac{1}{1}\times 0.003421 mol=0.003421 mol

Moles of NaOH = 0.003421 mole

Volume of NaOH solution = 43.92 ml = 0.04392 L ( 1 mL = 0.001L)

Concentration=\frac{Moles}{Volume(L)}

Concentration of NaOH :

\frac{0.003421 mol}{0.04392 L}=0.07789 M

0.07789 M is the sodium hydroxide concentration.

5 0
3 years ago
Suppose that the mixture in problem 4 is at 15 OC, where the pure vapor pressures are 12.5 mmHg for water and 32.1 mmHg for etha
EleoNora [17]

Answer:

Explanation:

Since we are not given the mole fraction of ethanol and water; we will solve this theoretically.

Using Raoult's Law:

P_A = (P_o)_A*X_A

For water:

(P)w = P_o \times \text{mole fraction of water}

where P_o of water = 12.5 mmHg

Then, the vapor pressure of water:

(P)w = 12.5 \ mmHg \times \text{mole fraction of water}

For ethanol:

P_E = P_o \times \text {mole fraction of ethanol}

and the P_o of ethanol = 32.1 mmHg

Then, the vapor pressure of ethanol:

P_E = 32.1 \ mmHg \times \text {mole fraction of ethanol}

The total vapor pressure T_P = P_W + P_E

The total vapor pressure = (12.5 \ mmHg \times \text{mole fraction of water}) + (32.1 \ mmHg \times \text {mole fraction of ethanol})

3 0
3 years ago
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