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3 years ago

What can be added to an atom to cause a nonvalence electron in the atom to temporarily become a valence electron?

Chemistry

2 answers:

Lilit [14]3 years ago

8 0

Answer:

Energy-

and it can be added to an atom to cause a non-valence electron in the atom to temporarily become a valence electron

vazorg [7]3 years ago

6 0

Answer:

What can be added to an atom to cause a nonvalence electron in the atom to temporarily become a valence electron is energy.

Explanation:

The normal state of the atoms, where all the electrons are occupying the lowest possible energy level, is called ground state.

The valence electrons are the electrons that occupy the outermost shell, this is the electrons in the highest main energy level (principal quantum number) of the atom.

So, a nonvalence electron occupies an orbital with less energy than what a valence electron does; in consequence, in order to a nonvalence electron jump from its lower energy level to the higher energy level of a valence electron, the former has to absorb (gain) energy.

This new state is called excited state and is temporary: the electron promoted to the higher energy level will emit the excess energy, in the form of light (photons), to come back to the lower energy level and so the atom return to the ground state.

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A solution of ammonia and water contains 2.60×1025 water molecules and 6.90×1024 ammonia molecules. how many total hydrogen atom

marshall27 [118]

1 molecule of NH3 has 3 atoms of H.
6.90*10²⁴ molecules NH3 have 3*6.90*10²⁴ =20.7*10²⁴ atoms H=2.07*10²⁵ atoms H

1 molecule H2O of has 2 atoms of H.
2.60*10²⁵ molecules of H2O have 2*2.60*10²⁵ =5.20 *10²⁵ atoms of H

2.07*10²⁵ + 5.20 *10²⁵ =7.27*10²⁵ atoms of H altogether.

4 0

2 years ago

6) (a) Calculate the absorbance of the solution if its concentration is 0.0278 M and its molar extinction coefficient is 35.9 L/

Anvisha [2.4K]

Answer:

6) (a) 0.499; (b) 31.7 %

7) 0.15

Explanation:

6) (a) Absorbance

Beer's Law is

$A = \epsilon cl\\A = \text{35.9 L&\cdot$mol$^{-1}$cm$^{-1}$} $\times$ 0.0278 mol$\cdot$L$^{-1} \times $ 0.5 cm = \mathbf{0.499}$

(b) Percent transmission

$A = \log {\left (\dfrac{1}{T}}\right)}\\\\\%T = 100T\\\\T = \dfrac{\%T}{100}\\\\\dfrac{1}{T} = \dfrac{100 }{\%T}\\\\A = \log \left(\dfrac{100 }{\%T} \right ) = 2 - \log \%T\\\\0.499 = 2 - \log \%T\\\\\log \%T = 2 - 0.499 = 1.501\\\\\%T = 10^{1.501} = \mathbf{31.7}$

7) Absorbance

$A = \log \left (\dfrac{I_{0}}{I} \right ) = \log \left (\dfrac{I_{0}}{0.70I_{0}} \right ) = \log \left (\dfrac{1}{0.70} \right ) = -\log(0.70) = \mathbf{0.15}}$

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3 years ago

Which compound has the lowest melting point? KCl CaCl2 Na2O C6H12O6

Alika [10]

It is called ethane.

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3 years ago

How many moles of iron in a sample that contains 7.91×10^23 atoms of iron?

vazorg [7]

Answer: 1.31

Explanation:

No.of moles = given no.of atoms/Avagadro number

= 7.91×10^23 / 6.022 x 10^23

= 1.31

therefore, no.of moles = 1.31

Hope it helped u,

pls mark as the brainliest

^_^

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2 years ago

if 2.0 g of hydrogen sulfide, H2S(g) reacts with 5.0 g of sodium hydroxide what mass of the excess reactant is present when the

Ronch [10]

Answer: iits 9.g

Explanation:

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