PLEASE HELP MEEEEEEEEEEEEEEEE!!!!!

lorasvet [3.4K]

Answer: $x = \frac{mn(q - p)}{n-m}\\\\$

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Work Shown:

Part 1

$\frac{x-m}{m} + p = \frac{x-n}{n} + q\\\\\frac{x-m}{m} - \frac{x-n}{n} = q - p\\\\\frac{n(x-m)}{mn} - \frac{m(x-n)}{mn} = q - p\\\\\frac{xn-mn}{mn} - \frac{xm-mn}{mn} = q - p\\\\\frac{xn-mn-(xm-mn)}{mn} = q - p\\\\$

Part 2

$\frac{xn-mn-xm+mn}{mn} = q - p\\\\\frac{xn-xm}{mn} = q - p\\\\\frac{x(n-m)}{mn} = q - p\\\\x(n-m) = mn(q - p)\\\\x = \frac{mn(q - p)}{n-m} \\\\$

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Explanations:

There are quite a bit of steps. I decided to break things into two parts.
The goal is to get x all by itself on its own side, which is why I subtracted (x-n)/n from both sides in part 1, step 2. I also subtracted p from both sides.
Afterward, I gave each fraction the LCD mn. I multiplied top and bottom of the first fraction by n/n. I did a similar operation to the second fraction, but with m instead.
From there, we distribute and simplify. The mn terms cancel on the left side numerator (second step of part 2).
The n≠m is there to prevent the denominator (n-m) from being zero. We cannot divide by zero.
If the formulas don't properly display, then you might have to refresh the page.

7 0

2 years ago

Select the correct location on the number line. Which point on the number line represents the approximate volume of a cylinder w

mart [117]

Answer:

the answer is 37.7 so the point closest to 40.

Step-by-step explanation:

5 0

3 years ago

Find the x-intercepts, use the zero product property, r(r+7)=0

UkoKoshka [18]

9514 1404 393

Answer:

r = 0

r = -7

Step-by-step explanation:

There is no x in the equation, hence there are no x-intercepts.

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If we assume you want the values of r that satisfy the equation, the zero product property tells you they will be the values that make the factors zero.

The factors are r and (r+7).

The factor r is zero when ...

r = 0

The factor (r+7) is zero when ...

r +7 = 0 ⇒ r = -7

The "x-intercepts" are r=0 and r=-7.

4 0

2 years ago

segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc

Elan Coil [88]

Answer:

The magnetic field is $B = 3.87 *10^{-6} \ T$

Direction is inward

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

The radius of BC is $r_{BC} = 30 \ cm = 0.30 \ m$

The radius of DA is $r _{DA} = 20 \ cm = 0.20 \ m$

The length of CD is $r_{CD} = 10 cm = 0.1 \ m$

The length of AB is $r_{AB} = 10 cm = 0.1 \ m$

The current is $I = 11.4A$

The magnetic field is mathematically represented as

$B = B_{BC} + B_{DA} + B_{CD} + B_{AB}$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]$

Where

$\theta_{BC} = \theta_{DA} = \frac{2\pi}{3}$

Where $\frac{2 \pi}{3} = 120^o$

$\theta_{CD} = \theta_{AB} = 0^o$

so

$B = \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]$

$B = 3.87 *10^{-6} \ T$

The direction is into the page

This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule the direction of current is perpendicular to the direction of magnetic field so since current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction

3 0

3 years ago

Need Help help me plz ;(

omeli [17]

So in order to solve you must first combine like terms.
-2y + 2y + 3 = 3
0 + 3 = 3
Subtract 3.
0 = 0
The answer is infinate solution because both numbers are the same.
I hope this helps love! :)

7 0

3 years ago