34/32 can also be written as 1.0625 or 1 & 1/16.
Answer:
-1 and -5
Step-by-step explanation:
You must account for negative u values (which the abs nullifies).
So
and
is what we have to solve for.
As for usual equations, isolate the u variable.
5u + 15 = 10
5u + 15 (-15) = 10 (-15)
5u = -5

u = -1
Now you can do the same operation for the other equation and you should get u = -5.
Let's make sure we did it right by replacing u with one of our solutions (-1 or -5).

That's true. What about the other one?

The distance traveled reported too high.
<h3>More</h3>

It has SI units m/s
The solution to the problem is as follows:
x^3-x^2 +x -1= x^2(x-1) +(x-1)=(x-1)(x^2+1) ,(common factor x-1
<span>
(x^2-1)=(x-1)(x+1) </span>
<span>
LCM=(x-1)(x^2+1)(x+1) </span>
<span>
=(x^2-1)(x^2+1)=x^4-1
I hope my answer has come to your help. God bless and have a nice day ahead!
</span>
You list the step by step and you're done.
Do you have an example??