A street has parallel curbs 40 feet apart. A crosswalk bounded by two parallel stripes crosses the street at an angle. The lengt
h of the curb between the stripes is 15 feet and each stripe is 50 feet long. Find the distance, in feet, between the strip
1 answer:
Answer:
The distance, in feet, between the strip = 12 feet.
Step-by-step explanation:
From the figure attached in relation with the question, we can deduce that crosswalk is a parallelogram where
CD/AB = CE/AE
CD = 40
CE = 50
AE = 15
Let AB = x
50x = 15 × 40
X = 12
The distance, in feet, between the strip is therefore 12 feet
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Answer:
Given: Quadrilateral P QR S is a rectangle.
To prove :PR= Q S
Construction : Join PR and Q S.
Proof: In Rectangle PQRS, and
→ taking two triangles PSR and Δ QRS
1. PS = Q R
2. ∠ PS R = ∠ Q RS [Each being 90°]
3. S R is common.
→ ΔP SR ≅ Δ Q RS → [Side-Angle-Side Congruency]
∴ PR =Q S [ corresponding part of congruent triangles ]
Hence proved.
