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4 years ago

Is the equation a proportuioanl relationship? x= 2y

1 answer:

3 0

A proportional change means that for every change in 1 value, it is accompanied by a change in another value that is the same every time. For example, with this, if x=1 then y=2*1=2. If we move x up 1 value to 2, y=2*2=4. Next, if we move x one more value up then 3*2=y=6. As you may notice, y adds up by 2 every time. In addition, you multiply the x value by the same number every time and only that number (no adding anything) and it is therefore a proportional equation

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Determine the open intervals on which the graph of f(x) = x - 4cos x is concave upward or concave downward

bazaltina [42]

The graph of the function $f(x)$ is

concave upward, when $f''(x)>0;$
concave downward, when $f''(x)$

Find $f''(x):$

$f'(x)=(x-4\cos x)'=1+4\sin x;$

$f''(x)=4\cos x.$

Now:

1. when $4\cos x>0,$ the graph of the function is concave upward and this is for

$x\in \left(-\dfrac{\pi}{2}+2\pi k,\dfrac{\pi}{2}+2\pi k\right), \text{ where } k\in Z.$

2. when $4\cos x$ the graph of the function is concave downward and this is for

$x\in \left(\dfrac{\pi}{2}+2\pi k,\dfrac{3\pi}{2}+2\pi k\right), \text{ where } k\in Z.$

6 0

3 years ago

A manufacturer inspects 500 personal video players and finds that 296 of them have no defects. the manufacturer sent a shipment

snow_tiger [21]

3351/500 = 6.702
296 times 6.702 is 1983.79
Answer is 1984

7 0

3 years ago

What is the quotient 1 5/8 ÷ -1 3/5

Shalnov [3]

Answer:

-1 1/64

Step-by-step explanation:

13/8 * - 5/8 = -65/64, or -1 1/64

I hope this helped, please mark Brainliest, thank you!!

5 0

3 years ago

For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?

Bond [772]

Given that $r=\theta$ , then $r'=1$

The slope of a tangent line in the polar coordinate is given by:

$m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}$

Thus, we have:

$m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}$

Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

$\sin\theta+\theta\cos\theta=0 \\ \\ \theta\cos\theta=-\sin\theta \\ \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta$

Therefore, the values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

θ = 0

θ = 2.02875783811043

θ = 4.91318043943488

Part B:

For vertical tangent lines, $\frac{1}{m} =0$

Thus, we have:

$\cos\theta-\theta\sin\theta=0 \\ \\ \Rightarrow\theta\sin\theta=\cos\theta \\ \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta$

Therefore, the values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

θ = 4.91718592528713

3 0

3 years ago

Rewrite the following polynomial in standard form 1 3 - 1 + x2

kifflom [539]

12 + x^2..............

7 0

3 years ago