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Romashka-Z-Leto [24]
4 years ago
7

Is the equation a proportuioanl relationship? x= 2y

Mathematics
1 answer:
prisoha [69]4 years ago
3 0
A proportional change means that for every change in 1 value, it is accompanied by a change in another value that is the same every time. For example, with this, if x=1 then y=2*1=2. If we move x up 1 value to 2, y=2*2=4. Next, if we move x one more value up then 3*2=y=6. As you may notice, y adds up by 2 every time. In addition, you multiply the x value by the same number every time and only that number (no adding anything) and it is therefore a proportional equation
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nekit [7.7K]

Answer:

3

Step-by-step explanation:

6/2=3

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7 − x −(−5x) − 10 + 4x
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8 x − 3

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Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

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Answer:

(2÷2)+4

step by step explanation

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Help please please please
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Answer:

10%

Step-by-step explanation:

10/100 = 1/10 = .1 = 10%

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