Question

Please help as fast as you can.

Answer 1

Answer:

$cos\theta$=$\sqrt{\frac{85}{121}}$

$tan\theta$=$\frac{6}{\sqrt{85}}$

Step-by-step explanation:

given, $sin\theta$=$\frac{6}{11}$

since, $sin^2\theta$+$cos^2\theta$=1

$cos^2\theta$=1-$sin^2theta$

$cos^2\theta[/tax]=1-[tex]\frac{36}{121}$

                                 =$\frac{121-36}{121}$

                                 =$\frac{85}{121}$

$cos\theta$=$\sqrt{\frac{85}{121}}$ answer

$tan\theta$=$\frac{sin\theta}{cos\theta}$

  $tan\theta$=$\frac{6}{\sqrt{85}}$  answer