Can u put a picture of the question with this so I can answer it.
Answer:
No, According to triangle Inequality theorem.
Step-by-step explanation:
Given:
Length given are 4 in., 5 in., 1 in.
We need to check whether with these lengths we can create triangular components.
The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side.
These must be valid for all three sides.
Hence we will check for all three side,
4 in + 5 in > 1 in. (It is a Valid Condition)
1 in + 5 in > 4 in. (It is a Valid Condition)
4 in + 1 in > 5 in. (It is not a Valid Condition)
Since 2 condition are valid and 1 condition is not we can say;
A triangular component cannot be created with length 4 in, 5 in, and 1 in by using triangle inequality theorem (since all three conditions must be valid).
The diameter can be obtained by the formula A = pi*r^2
First, multiply 0.50 * 100 to obtain the area of the ball, then simplify and solve for the radius. Doubling the radius would yield the diameter. This is shown below:
Area of the ball = 0.50 * 100 = 50 in^2
<span>A = pi*r^2
</span>50 = (3.14)*r^2
r = 3.99 = approx. 4
diameter = 2r
Diameter = 8 inches.
Among the choices, the correct answer is C. 8.0 in.
Answer:
Step-by-step explanation:
<u>We observe two angles and the included side of ABC are congruent to two angles and the included side of DBE:</u>
This is called ASA
The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx 28.27 sq in.
Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.
The difference is 52.73 sq in; the square is larger, the circle smaller.
