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Valentin [98]
4 years ago
6

To French shop for fresh fruit. Elena buys a watermelon for $7.75 and 5 pounds of cherries Tammy buys a pineapple for $4.15 and

4 pounds of cherries. Use the variable peer to represent the price in dollars per pound of cherries. Right and simplify and expression to represent how much more Alina spent
Mathematics
1 answer:
lys-0071 [83]4 years ago
8 0

Answer: Elena spent $3.6 +x more than Tammy.

Step-by-step explanation:

Let the cost of each cherry be 'x'.

Cost of watermelon for Elena = $7.75

Cost of 5 pounds of cherries = 5x

So, Equation for Elena would be

7.75+5x

Cost of pineapple = $4.15

Number of pounds of cherries = 4

So, Equation for Tammy would be

\$4.15+4x

Now, Elena spent more than Tammy by

(7.75+5x)-(4.15+4x)\\\\=7.75+5x-4.15-4x\\\\=3.6+x

Hence, Elena spent $3.6 +x more than Tammy.

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Find the area (hint: find the value of x first)
lidiya [134]

Answer:

C. 128 in²

Step-by-step explanation:

We know that the opposite sides of rectangles are congruent, so 8 = 2x. If we divide 8 by 2 and 2x by 2, we get x = 4.

  • This means that the other side length, (3x + 4), equals 3(4) + 4 = 12 + 4 = 16 inches

Now, the area of a rectangle is l × w, where l = length and w = width. The dimensions of this rectangle are 8 and 16, so 8 × 16 = 128 in².

5 0
2 years ago
The Westminster Widget Company has an old machine that can produce 50 widgets in five hours. Now they have purchased a
Norma-Jean [14]

<u>Answer: </u>

If they worked together it would take 4 hours for the machines to produce 100 widgets

<u>Step-by-step explanation:</u>

w = widgets     hr = hour     ph = per hour

Old machine - 50w = 5hr = 10ph

New machine - 30w = 2hr = 15ph

Old machine - 20w = 2hr

New machine - 30w = 2hr

<h3>Together  - 50w = 2hr x 2 </h3><h3>              Final:  100w = 4hr</h3>

     I hope this helped!

8 0
2 years ago
The rectangle below has an area of x^2 - 9 square meters and a width of x - 3 meters.
Rama09 [41]

Answer:

x+3

Step-by-step explanation:

Area of a rectangle is L\cdot W.

We know the width, W, is x-3 and we know the area is x^2-9.

Inputting this in our formula above we get:

x^2-9=L(x-3)

L is a an expression such that when you multiply it to (x-3) gives you (x^2-9).

x^2-9 is a difference of squares and can be factored using:

a^2-b^2=(a-b)(a+b).

x^2-9=(x-3)(x+3).

So L=x-3 and W=x+3.

4 0
3 years ago
PLEASE HELP! I will give brainliest
harkovskaia [24]
<h3>3 Answers:</h3>

A) y intercept is (0,3)

C) Axis of symmetry is x = -1

D) Vertex is (-1, 4)

So basically everything but choice B is true.

========================================

Explanation:

Choice A is true because plugging in x = 0 leads to y = 3. Effectively, anything with an x goes away when x = 0 leaving that 3 behind. So finding the y intercept in this form is fairly fast.

-------------------

To check choices B through D, let's convert the equation into vertex form.

y = -1x^2 - 2x + 3 is in the form y = ax^2 + bx + c where

a = -1

b = -2

c = 3

The vertex is located at (h,k) such that h = -b/(2a)

Plug the values of 'a' and 'b' into the equation below

h = -b/(2a)

h = -(-2)/(2*(-1))

h = 2/(-2)

h = -1

The x coordinate of the vertex is x = -1

Then use this to find the y coordinate of the vertex

y = -1x^2 - 2x + 3

y = -1(-1)^2 - 2(-1) + 3

y = 4

The y coordinate of the vertex is 4, meaning k = 4

The vertex overall is (h,k) = (-1, 4)

This shows choice D is true, meaning choice B has to be false.

Choice C is true because the axis of symmetry is the x coordinate of the vertex. This is the vertical line that cuts the parabola into two mirrored halves. This vertical line always goes through the vertex.

5 0
3 years ago
I'm stuck on a.<br>please help me!!!!​
agasfer [191]

You have to estimate the slope of the tangent line to the graph at <em>t</em> = 10 s. To do that, you can use points on the graph very close to <em>t</em> = 10 s, essentially applying the mean value theorem.

The MVT says that for some time <em>t</em> between two fixed instances <em>a</em> and <em>b</em>, one can guarantee that the slope of the secant line through (<em>a</em>, <em>v(a)</em> ) and (<em>b</em>, <em>v(b)</em> ) is equal to the slope of the tangent line through <em>t</em>. In this case, this would be saying that the <em>instantaneous</em> acceleration at <em>t</em> = 10 s is approximately equal to the <em>average</em> acceleration over some interval surrounding <em>t</em> = 10 s. The smaller the interval, the better the approximation.

For instance, the plot suggests that the velocity at <em>t</em> = 9 s is nearly 45 m/s, while the velocity at <em>t</em> = 11 s is nearly 47 m/s. Then the average acceleration over this interval is

(47 m/s - 45 m/s) / (11 s - 9 s) = (2 m/s) / (2 s) = 1 m/s²

7 0
3 years ago
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