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3 years ago

5

Jorge baked cookies for his math class's end-of-year party. There are 28 people in Jorge's math class including Jorge and his te

acher. Jorge baked enough cookies for everyone to get 3 cookies each. How many cookies did Jorge bake?

1 answer:

timurjin [86]3 years ago

7 0

You have to multiply the number of people times the number of cookies they are each supposed to get

So, 28 x 3 = 84 cookies

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Which expression is equivalent to square root 55x^7y6/11x^11y^8

Novay_Z [31]

Answer:

$\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}$

Step-by-step explanation:

$\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a$

$=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}$

6 0

2 years ago

I go bowling every week and keep track of how many strikes i get: 2,0,4,7,7,0,1,0 Find the mode median and mean of this set of d

natima [27]

Answer:

<em>Mode is 0</em>
<em>Median is 1 </em>
<em>Mean is 2.625</em>

Step-by-step explanation:

<em>To find the mode, or modal value, it is best to put the numbers in order. A number that appears most often is the mode.</em>
<em>0, 0, 0, 1, 2, 4, 7, 7 = mode is 0</em>

<em></em>

<em>To find the Median, place the numbers in value order and find the middle number.</em>
<em>0 , 0 , 0 , 1 , 2 , 4 , 7 , 7 = median is 1</em>

<em></em>

<em>The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are.</em>
<em>0 + 0 + 0 + 1 + 2 + 4 + 7 + 7 / 8 = mean is 2.625</em>

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2 years ago

Anyone got answers need help

Mkey [24]

∠DCE = ∠BAE because of alternate interior ∠s

∠CDE = ∠ABE because of alternate interior ∠s

Triangle DCE is congruent to Triangle BAE because of ASA

AE = CE because of CPCTC

BE = DE because of CPCTC

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3 years ago

ℓ=gT24π2 what is g equal to

V125BC [204]

If $a=48Tg\pi$ then $g=\frac{a}{48T\pi}$ .

Hope this helps.

4 0

3 years ago

The half-life of a certain radioactive material is 83 hours. An initial amount of the material has a mass of 67 kg. Write an exp

Anvisha [2.4K]

Answer:

Initial amount of the material is 67 kg
Hal-life is 83 hours

<u>The required equation is:</u>

m(x) = 67 * $(1/2)^{x/83}$ , where m- remaining amount of the radioactive material, x - number of hours

<u>After 5 hours the material remains:</u>

m(5) = 67 * $(1/2)^{5/83}$ = 64.260 (rounded)

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2 years ago