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3 years ago

Please Help!! What is the factorization of the polynomial below?

Mathematics

2 answers:

VARVARA [1.3K]3 years ago

8 0

The answer is B which is (x-9)(x+4)

Advocard [28]3 years ago

7 0

The answer is B. (x - 9)(x + 4)
To factorise quadratic expressions, you first need to find factors of the end number, in this case 36, that have a difference of the middle number, which is 5. The two factors in this expression are 4 and 9, because 9 - 4 = 5. As for the signs, you know by the end sign that they are different, and the middle sign means that the biggest number is negative, which gives you your (x - 9)(x + 4)

I hope this helps!

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Fiesta28 [93]

So 35-8 is 27. 27 divided by 3 is 9.

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4 years ago

Please help thank you! will give brainliest!

VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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7 0

2 years ago

If a 30 foot ladder is positioned so that the bottom of the ladder is 1/4 of its length away from the wall, how far up the wall

Dvinal [7]

Answer:

29.05 ft

Step-by-step explanation:

Using the concept of pythagoras theorem, here we have the base and hypotenuse given hence we need to find the third dimension, assuming the wall is perfectly straight and forms a right angle with the bsse of the ladder. Here, $c^{2}=a^{2}+b^{2}$ and making a the subject of the formula then $a=\sqrt {c^{2}-b^{2}}$ and substituting 30 ft for c and 0.25*30=7.5 ft for b then $a=\sqrt {30^{2}-7.5^{2}}=\sqrt {843.75}=29.047375096555626\approx 29.05 ft$

7 0

3 years ago

If a triangle is 12 inches high and has a 20 inch long hypotenuse then how wide is it?

Ber [7]

Answer:

The triangle should be 16 inches wide.

Step-by-step explanation:

$\text {Use the Pythagorean Theorem to solve for the leg.}\\a^2 + b^2 =c^2$

What we know:

One of the legs measures 12 inches.

The hypotenuse is 20 inches.

We need to solve for b. Solving for a while b is 12 would also be acceptable.

$12^2 + b^2 = 20^2 \text { OR } a^2 +12^2=20^2$

We will use the first equation.

$12^2 + b^2 = 20^2\\12 * 12 = 144\\20 * 20 = 400\\\\\boxed {144 + b^2 = 400}$

$\text {Subtraction property of equality: }\\144-144+ b^2 = 400-144\\\boxed {b^2 = 256}\\\\\text {Take the square root of 256: }\\\sqrt{256}=\sqrt{b^2} \boxed {16 = b}$

The triangle should be 16 inches wide.

3 0

4 years ago

Use the equation below to find y, if m=4, x = 3, and b=11. <br><br> Y = mx + b

VLD [36.1K]

Answer:

y = 23

Step-by-step explanation:

Assuming the equation not below is y = mx + b form...

m = 4

x = 3

b = 11

y = 4(3) + 11

y = 12+ 11

y = 23

3 0

4 years ago