Question

Evaluate 6+\dfrac4a+\dfrac b36+ a 4 ​ + 3 b ​ 6, plus, start fraction, 4, divided by, a, end fraction, plus, start fraction, b, divided by, 3, end fraction when a=4a=4a, equals, 4 and b=3b=3b, equals, 3.

Answer 1

Answer:

8

Step-by-step explanation:

The given expression can be written as :

$6+\dfrac{4}{a}+\dfrac{b}{3}$

We need to find the value of the above expression when a = 4 and b = 3

Put a = 4 and b = 3 in the given expression

$6+\dfrac{4}{a}+\dfrac{b}{3}=6+\dfrac{4}{4}+\dfrac{3}{3}\\\\=6+1+1\\\\=8$

So, the value of the given expression is 8.