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oee [108]
3 years ago
10

7➗1/5 As a fraction plz

Mathematics
2 answers:
Leno4ka [110]3 years ago
6 0

Answer:

35/1 or 35

Step-by-step explanation:

•Remember this. Keep, Change, and Flip.

•Write 7/1, you keep this fraction.

•Change division sign into multiplication sign.

• Flip 1/5 into the reciprocal which is 5/1.

•Now multiply 7/1 x 5/1 7 times 5 equals 35 over one.

• Boom its 35/1 or 35

marishachu [46]3 years ago
5 0

\bf 7\div \cfrac{1}{5}\implies \cfrac{7}{1}\div \cfrac{1}{5}\implies \cfrac{7}{1}\cdot \cfrac{5}{1}\implies \cfrac{35}{1}

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The manufacturer of an airport baggage scanning machine claims it can handle an average of 530 bags per hour. (a-1) At α = .05 i
fenix001 [56]

Answer:

Null hypothesis:\mu \geq 250        

Alternative hypothesis:\mu < 250  

p_v =P(t_{15}    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significantly lower than 530 at 5% of significance.      

Step-by-step explanation:

1) Data given and notation        

\bar X=510 represent the mean for the sample    

s=50 represent the standard deviation for the sample  

n=16 sample size        

\mu_o =530 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.      

t would represent the statistic (variable of interest)        

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.        

We need to conduct a hypothesis in order to determine if the claim thet the handle on average is 530 bags per hour:      

Null hypothesis:\mu \geq 530        

Alternative hypothesis:\mu < 530        

We don't know the population deviation and the sample size is lees than 30, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:        

t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)        

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic        

We can replace in formula (1) the info given like this:        

t=\frac{510-530}{\frac{50}{\sqrt{16}}}=-1.60        

4) Calculate the critical value

We need to begin calculating the degrees of freedom

df=n-1=16-1=15

The critical value for this case would be :

P(t_{15}

The value of a that satisfy this on the normal standard distribution is a=-1.75 and would be the critical value on this case zc=-1.75

5) Calculate the P-value        

Since is a one-side upper test the p value would be:        

p_v =P(t_{15}    

6) Conclusion        

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significantly lower than 530 at 5% of significance.      

8 0
2 years ago
Guys plz help me answer this!!!
ddd [48]

Answer:           number 2

cuz its the only one that makes sense

5 0
2 years ago
In each box is a step in the process of solving a max/min problem like the one in Question 8. Number these steps in order (1-8)
Dmitriy789 [7]

Answer:

The steps are numbered below

Step-by-step explanation:

To solve a maximum/minimum problem, the steps are as follows.

1. Make a drawing.

2. Assign variables to quantities that change.

3. Identify and write down a formula for the quantity that is being optimized.

4. Identify the endpoints, that is, the domain of the function being optimized.

5. Identify the constraint equation.

6. Use the constraint equation to write a new formula for the quantity being optimized that is a function of one variable.

7. Find the derivative and then the critical points of the function being optimized.

8. Evaluate the y-values of the critical points and endpoints by plugging them into the function being optimized. The largest y- value is the global maximum, and the smallest y-value is the global minimum.

8 0
2 years ago
I am trying to solve for x
padilas [110]
Here how i found my answer.

5 0
3 years ago
Simplify.<br><br>1 – 2u + u + 4​
liq [111]

Answer:

-u+5

Step-by-step explanation:

plz mark as brainliest

5 0
2 years ago
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