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3 years ago

7➗1/5 As a fraction plz

Mathematics

2 answers:

Leno4ka [110]3 years ago

6 0

Answer:

35/1 or 35

Step-by-step explanation:

•Remember this. Keep, Change, and Flip.

•Write 7/1, you keep this fraction.

•Change division sign into multiplication sign.

• Flip 1/5 into the reciprocal which is 5/1.

•Now multiply 7/1 x 5/1 7 times 5 equals 35 over one.

• Boom its 35/1 or 35

marishachu [46]3 years ago

5 0

$\bf 7\div \cfrac{1}{5}\implies \cfrac{7}{1}\div \cfrac{1}{5}\implies \cfrac{7}{1}\cdot \cfrac{5}{1}\implies \cfrac{35}{1}$

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The manufacturer of an airport baggage scanning machine claims it can handle an average of 530 bags per hour. (a-1) At α = .05 i

fenix001 [56]

Answer:

Null hypothesis: $\mu \geq 250$

Alternative hypothesis: $\mu < 250$

$p_v =P(t_{15}$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significantly lower than 530 at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=510$ represent the mean for the sample

$s=50$ represent the standard deviation for the sample

$n=16$ sample size

$\mu_o =530$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the claim thet the handle on average is 530 bags per hour:

Null hypothesis: $\mu \geq 530$

Alternative hypothesis: $\mu < 530$

We don't know the population deviation and the sample size is lees than 30, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{510-530}{\frac{50}{\sqrt{16}}}=-1.60$

4) Calculate the critical value

We need to begin calculating the degrees of freedom

$df=n-1=16-1=15$

The critical value for this case would be :

$P(t_{15}$

The value of a that satisfy this on the normal standard distribution is a=-1.75 and would be the critical value on this case zc=-1.75

5) Calculate the P-value

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}$

6) Conclusion

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2 years ago

Guys plz help me answer this!!!

ddd [48]

Answer: number 2

cuz its the only one that makes sense

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2 years ago

In each box is a step in the process of solving a max/min problem like the one in Question 8. Number these steps in order (1-8)

Dmitriy789 [7]

Answer:

The steps are numbered below

Step-by-step explanation:

To solve a maximum/minimum problem, the steps are as follows.

1. Make a drawing.

2. Assign variables to quantities that change.

3. Identify and write down a formula for the quantity that is being optimized.

4. Identify the endpoints, that is, the domain of the function being optimized.

5. Identify the constraint equation.

6. Use the constraint equation to write a new formula for the quantity being optimized that is a function of one variable.

7. Find the derivative and then the critical points of the function being optimized.

8. Evaluate the y-values of the critical points and endpoints by plugging them into the function being optimized. The largest y- value is the global maximum, and the smallest y-value is the global minimum.

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padilas [110]

Here how i found my answer.