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matrenka [14]
3 years ago
5

What properties does a square have in common with a quadrilateral?

Mathematics
1 answer:
Igoryamba3 years ago
7 0
Both have 4 sides 4 corners and both of them have two pairs of sides running parallel to each other.
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If the revenue for the week is $2000, and labor cost consists of two workers earning $8 per hour who work 40hours each, what is
Arada [10]
The percentage of the revenue is 32% hope this helps!
4 0
3 years ago
Given ΔKLM with lengths as marked, what is the relationship of segment NO to segment KL?
Oliga [24]

Segment NO is parallel to the segment KL.

Solution:

Given KLM is a triangle.

MN = NK and MO = OL

It clearly shows that NO is the mid-segment of ΔKLM.

By mid-segment theorem,

<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>

⇒ NO || KL and NO = \frac{1}{2}KL

Therefore segment NO is parallel to the segment KL.

6 0
3 years ago
A bag of concrete equals 1000 cu. Inches. Your customer already has 2 bags at home. How many more bags does he need to fill an a
adelina 88 [10]
From the information given;
1 bag of concrete = 1000 in^3
2 bags at home = 1000*2 = 2000 in^3

The available space has a volume of;

Volume = (5*12)*10*10 (Note: 1 ft = 12 inches)
Volume = 60*10*10 = 6000 in^3

The remaining volume = Available space - occupied space = 6000 - 2000 = 4000 in^2

1 bag = 1000 in^3
x bags = 4000 in^2

Then,
x = 1*4000/1000 = 4 bags.
This means 4 more bags of concrete will be required to fully fill the  space.
5 0
3 years ago
Answer correctly
lara31 [8.8K]

6w-10 represents the total amount of fence will need to complete the rectangle of fence in his yard. The fence will need two lengths and 2 widths to complete the rectangle. If the width is w, and the length is 2w-5, then the total for the rectangle would be w+w+2w-5+2w-5 which simplifies to 6w-10.

7 0
3 years ago
Read 2 more answers
a rectangular corn hole area at the recreation center has a width of 5 feet and a length of 10 feet. if a uniform amount is adde
harkovskaia [24]
Let
x-------------> amount added <span>to each side
</span>A-------------> area increased----------> 84 ft²

we know that
A=(10+x)*(5+x)=84-----------> 10*5+10*x+5*x+x²
50+15x+x²=84----------> x²+15x-34=0
<span>solving the second order equation
</span>x1=-17
x2=2

 the answer is x=2 ft
3 0
3 years ago
Read 2 more answers
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