We know that the points at which the parabola intersects the x axis are
(-5,0) and (1,0)
So the extent between these two points would be the base of the triangle
lets find the length of the base using the distance formula
![\sqrt{[(-5-1)^{2}+(0-0)^{2} ]}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B%28-5-1%29%5E%7B2%7D%2B%280-0%29%5E%7B2%7D%20%5D%7D%20%20)
the base b=6
We will get the height of the triangle when we put x=0 in the equation
y=a(0+5)(0-1)
y=-5a
so height = -5a (we take +5a since it is the height)
We know that the area of the triangle =
× 6 × (5a) = 12
15a=12
a= 
Answer:
34
Step-by-step explanation:
The answers would be A D and E because if you were to flip them onto each other they would be the exact same
Answer:
Step-by-step explanation:
56.27 =
50
+ 6
+ 0.2
+ 0.07
Expanded Factors Form:
56.27 =
5 × 10
+ 6 × 1
+ 2 × 0.1
+ 7 × 0.01
Expanded Exponential Form:
56.27 =
5 × 101
+ 6 × 100
+ 2 × 10-1
+ 7 × 10-2
Word Form:
56.27 =
fifty-six and twenty-seven hundredths
Answer:
f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola. ... When written in "vertex form": • (h, k) is the vertex of the parabola, and x = h is the axis of symmetry.
