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3 years ago

14

Is the statement (35)4 = (34)5 true?

2 answers:

Anna [14]3 years ago

7 0

Answer:

No.

Step-by-step explanation:

35(4) = 140

34(5) = 170

140 does not equal 170, therefore it is NOT TRUE

RoseWind [281]3 years ago

4 0

It is not equal so the answer to this is not true

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Twice the sum of a number and 5 <br>

mash [69]

Answer:

2(x+5)

Step-by-step explanation:

6 0

3 years ago

Enter your answer in the box. Be sure to enter your answer as an ordered pair (x,y). Meaning, put your answer in parenthesis.

vitfil [10]

Answer:

The solution of the system of equation are (10,15).

Step-by-step explanation:

The given two linear two variable equations are

- x - 2y = - 40 ........ (1) and

x + 4y = 70 .......... (2)

Now,adding thoes two equations (1) and (2) we get,

- 2y + 4y = - 40 + 70

⇒ 2y = 30

⇒ y = 15.

Now, putting y = 15 in the equation (2), we get,

x = 70 - 4y = 70 - 4(15) = 10

Therefore, the solution of the system of equation are (10,15). (Answer)

3 0

4 years ago

Can someone help me find x

Viefleur [7K]

Answer:

Rounded to the nearest tenth: $x=5.7$ in

Rounded to the nearest hundredth: $x=5.74$ in

Step-by-step explanation:

We have a right triangle with a given angle of 35°. We also have the opposite side of that angle, $x$ , and its hypotenuse 10 in. To find $x$ , we are using the trig function that relates the opposite side with the hypotenuse; in other words, the sine trig function.

$sin\alpha =\frac{opposite}{hypotenuse}$

$sin(35)=\frac{x}{10}$

$x=10sin(35)$

$x=5.735764364$

Rounded to the nearest tenth: $x=5.7$ in

Rounded to the nearest hundredth: $x=5.74$ in

4 0

3 years ago

Eliminate the parameter and write a rectangular equation for.

Artyom0805 [142]

Eliminate the parameter t:t=y/2
x=y^2/2+3

8 0

4 years ago

A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum heigh

Stella [2.4K]

A parabola is a mirror-symmetrical U-shape.

The equation of the parabola is $\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$
The focus is $\mathbf{Focus = (80, -1760)}$
The directrix is $\mathbf{y = \frac{1}{640}}$
The axis of the symmetry of parabola is: $\mathbf{x = 80}$

From the question, we have:

$\mathbf{Vertex: (h,k) = (80,10)}$

$\mathbf{Origin: (x,y) = (0,0)}$

The equation of a parabola is:

$\mathbf{y = a(x - h)^2 + k}$

Substitute the values of origin and vertex in $\mathbf{y = a(x - h)^2 + k}$

$\mathbf{0 = a(0 - 80)^2 + 10}$

$\mathbf{0 = a(- 80)^2 + 10}$

$\mathbf{0 = 6400a + 10}$

Collect like terms

$\mathbf{6400a =- 10}$

Solve for a

$\mathbf{a =- \frac{1}{640}}$

Substitute the values of a and the vertex in $\mathbf{y = a(x - h)^2 + k}$

$\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$

The focus of a parabola is:

$\mathbf{Focus = (h, \frac{k+1}{4a})}$

Substitute the values of a and the vertex in $\mathbf{Focus = (h, \frac{k+1}{4a})}$

$\mathbf{Focus = (80, \frac{10+1}{4 \times -\frac{1}{640}})}$

$\mathbf{Focus = (80, -\frac{11}{\frac{1}{160}})}$

$\mathbf{Focus = (80, -11\times 160)}$

$\mathbf{Focus = (80, -1760)}$

The equation of the directrix is:

$\mathbf{y = -a}$

So, we have:

$\mathbf{y = \frac{1}{640}}$ ----- the directrix

The axis of symmetry is:

$\mathbf{x = -\frac{b}{2a}}$

We have:

$\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$

Expand

$\mathbf{y = -\frac{1}{640}(x^2 -160x + 6400) +10}$

Expand

$\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x - 10 +10}$

$\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x }$

A quadratic function is represented as:

$\mathbf{y = ax^2 + bx + c}$

So, we have:

$\mathbf{a = -\frac{1}{640}}$

$\mathbf{b = \frac{1}{4}}$

Recall that:

$\mathbf{x = -\frac{b}{2a}}$

So, we have:

$\mathbf{x = -\frac{1/4}{2 \times -1/640}}$

$\mathbf{x = \frac{1/4}{1/320}}$

This gives

$\mathbf{x = \frac{320}{4}}$

$\mathbf{x = 80}$

Hence, the axis of the symmetry of parabola is: $\mathbf{x = 80}$

Read more about parabola at:

brainly.com/question/21685473

6 0

3 years ago