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zvonat [6]
3 years ago
15

9e−7=7e−11 need help homework

Mathematics
1 answer:
german3 years ago
3 0

9e−7=7e−11

9e-7+11=7e-11+11

9e+4-9e=7e-9e

4/-2=-2e/-2

-2=e

no solution

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If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. The thrid num
weeeeeb [17]

Answer:

<h2>x = 0, y = 5, z = 3</h2>

Step-by-step explanation:

x,\ y,\ z-\text{three numbers}\\\\\left\{\begin{array}{ccc}(x+2z)-y=1&(1)\\z+2x=3&(2)\\x+3y+z=18&(3)\end{array}\right\\\\(2)\\z+2x=3\qquad\text{subtract}\ 2x\ \text{from both sides}\\z=3-2x\qquad(*)\\\\\text{Substitute}\ (*)\ \text{to (1) and (3)}\\\\\left\{\begin{array}{ccc}x+2(3-2x)-y=1&\text{use the distributive property}\\x+3y+(3-2x)=18\end{array}\right

\left\{\begin{array}{ccc}x+(2)(3)+(2)(-2x)-y=1\\x+3y+3-2x=18&\text{subtract 3 from both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+6-4x-y=1&\text{subtract 6 from both sides}\\(x-2x)+3y=15\end{array}\right\\\left\{\begin{array}{ccc}(x-4x)-y=-5\\-x+3y=15\end{array}\right\\\left\{\begin{array}{ccc}-3x-y=-5&\text{multiply both sides by 3}\\-x+3y=15\end{array}\right

\underline{+\left\{\begin{array}{ccc}-9x-3y=-15\\-x+3y=15\end{array}\right}\qquad\text{add all sides of the equations}\\.\qquad-10x=0\qquad\text{divide both sides by (-10)}\\.\qquad\boxed{x=0}\\\\\text{Put it to the second equation:}\\-0+3y=15\\3y=15\qquad\text{divide both sides by 3}\\\boxed{y=5}\\\\\text{Put the value of}\ x\ \text{to}\ (*):\\\\z=3-2(0)\\\boxed{z=3}

7 0
3 years ago
50 POINTS!! HELP!
Minchanka [31]

i dont have time to do all of it (sorry)

but this is how you do the point and slope questions:

use the equation: y-y1 = m(x - x1)

y1 is the y point you are given

x1 is the x point you are given

m is your slope

substitute all of those in from the question

the first one is:

y --4 = -5/6(x-8)

-- turns into a plus so the answer would be

y+4 = -5/6(x-8)

6 0
2 years ago
Find the slope of the line through each pair of points (11, 18) (20, 12)
JulijaS [17]

Answer:

2/3

Step-by-step explanation:

We can find the slope by using the slope formula

m = ( y2-y1)/(x2-x1)

   = ( 12-18)/(20 -11)

   = -6/-9

 = 2/3

3 0
2 years ago
PLLEASEEEE ANSWER HURRY
Galina-37 [17]
The answer is y=-8 I’m pretty sure
6 0
3 years ago
Suppose you have 100 ft of string to rope off a rectangular section for a bake sale at a school Fair. The function A=x^2+50x giv
cupoosta [38]

Answer:

Therefore the width is 25 feet for getting maximum area.

The maximum area of the rectangle is 625 square feet.

Therefore the range is 0≤A≤625.

Step-by-step explanation:

Given function is

A = - x²+50x

We know that ,

If y = ax²+bx+c

For the maximum x=-\frac{b}{2a}

Here a = -1 , b= 50 and c=0

Therefore the width x= -\frac{50}{2.(-1)} = 25

Therefore the width is 25 feet for getting maximum area.

The maximum area =[ -(25)²+50.25] square feet

                                 = 625 square feet

The area can not be negative and maximum area is 625 square feet.

Therefore the range is 0≤A≤625.

5 0
3 years ago
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