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3 years ago

8 + 3 + 4) = 8 + (4+3) what property is this

1 answer:

5 0

This property is associative because you can group the numbers in any order and add them and you will still get the same answer.

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3 years ago

Read 2 more answers

I want only question number 3

zmey [24]

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Step-by-step explanation: to graph y=23.5x you just plug in numbers. If x = 1, 23.5 (1), which equals y. Now you can keep doing this to get up to 4. You may use a calculator if youd like.

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3 years ago

Use the given parallelogram to find the length of side AB. A parallelogram has vertices A B C D. Side A B is labeled x plus 3, a

vekshin1

Answer:

Step-by-step explanation:

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3 years ago

Simplify. (x6 y3)(−8xy2)(−6x3)

meriva

When simplifying this, we would have to take this little by little in serious steps and not only this, but to also take notice of the use of pemdas and to make sure that we take each step carefully.

We first would (first) simplify the following:

$(((x^6)*(y^3))*(0-(8x*(y^2))))*(0-(2*3x^3)) \\ \\ then \ we \ would \ do . . . . \\ \\ x^7 \ multiplied \ by \ x^3 \ = x^(^7^ +^ 3^) = \ x^1^0 \\ \\ (last \ step).... \\ \\ 2^3 \ multiplied \ by \ 2^1 = 2^(^3^ +^ 1^) = 2^4 \\ \\ \Longrightarrow \ (your \ answer) \\ \\ \boxed{\bf{ (2^4*3x^1^0y^5)}}$

7 0

4 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

8 0

3 years ago