(0.7) exponent 2 please help!

10. Given that the total distance travelled is 4 km and that the initial aceleration is 4 m/s², find:a) the value of V.b) the va

andrezito [222]

The initial deceleration is 4 m/s^2, so this means that considering the first line segment, $\frac{V-100}{T}=-4 \implies V=100-4T$ .

The total distance traveled is 4 km, which is equal to 4000 meters. This is equal to the area under the graph, so $400T-\frac{1}{2}(100-V)(5T)=4000$ .

$400(100-4T)-\frac{1}{2}(4T)(5T)=4000\\\\40000-1600T-10T^2=4000\\\\10T^2 +1600T-36000=0\\\\T^2 +160T-3600=0\\\\(T+180)(T-20)=0\\\\T=20 (T > 0)\\\\\therefore V=100-4(20)=20$

6 0

1 year ago

(sin teta + sec teta)^ + (cos teta+ cosec teta )^ = (1 + sec x cosec)^

ArbitrLikvidat [17]

$(sin\theta+sec\theta)^2+(cos\theta+cosec\theta)^2=(1+sec\theta\ cosec\theta)^2\\\\L=sin^2\theta+2sin\theta\cdot\frac{1}{cos\thewta}+\frac{1}{cos^2\theta}+cos^2\theta+2cos\theta\cdot\frac{1}{sin\theta}+\frac{1}{sin^2\theta}\\\\=(sin^2\theta+cos^2\theta)+\frac{2sin\theta}{cos\theta}+\frac{2cos\theta}{sin\theta}+\frac{1}{cos^2\theta}+\frac{1}{sin^2\theta}$

$=1+\frac{2sin^2\theta+2cos^2\theta}{sin\theta\ cos\theta}+\frac{sin^2\theta+cos^2\theta}{sin^2\theta\ cos^2\theta}\\\\=1+\frac{2(sin^2\theta+cos^2\theta)}{sin\theta\ cos\theta}+\frac{1}{sin^2\theta\ cos^2\theta}\\\\=1+\frac{2}{sin\theta\ cos\theta}+\frac{1}{sin^2\theta\ cos^2\theta}\\\\=1^2+2sec\theta\ cosec\theta+sec^2\theta\ cosec^2\theta\\\\=(1+sec\theta\ cosec\theta)^2=R$

4 0

4 years ago

on a map, each centimeter represents 45 kilometers. two towns are 135 kilometers apart. what is the distance between the towns o

Anastasy [175]

1 cm = 45 km
x cm = 135 km

135/45 = 3 cm

distance between the towns on the map is 3 cm.

i hope this helps :)

8 0

3 years ago

The captain of a boat knows that a lighthouse on the coast is 100 ft. tall. If he measures the angle of elevation to be 2 degree

faltersainse [42]

Answer and Step-by-step explanation:

| \

| \

100 ft. | \

| 2 \

|_________\

x

Use tangent to find the x.

tan(2) = $\frac{100}{x}$

$x = \frac{100}{tan(2)}$

Use a calculator to evaluate.

$x = \frac{100}{tan(2)}$ = 2863.6253

So, the boat is 2,863.63 feet from the shore.

#teamtrees #WAP (Water And Plant)

6 0

3 years ago

Mr. Vara is designing post caps in the shape of a square pyramid for a fence that he just built in his backyard. The caps are so

Lyrx [107]

Answer:

Height of the square pyramid is 6.569 centimeter

Step-by-step explanation:

The volume of the square pyramid is 94.5 cubic centimeters

The height of the square pyramid will be equal to the lengths of the sides of the square.

The volume of the square pyramid is given by

$a^2 * \frac{h}{3}$

or

$\frac{a^3}{3} = 94.5\\a^3 = 94.5 *3\\a = \sqrt[3]{94.5*3} \\a = 6.569$ centimeter

Height of the square pyramid is 6.569 centimeter

3 0

3 years ago