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3 years ago

(0.7) exponent 2 please help!

Mathematics

1 answer:

ratelena [41]3 years ago

7 0

The answer is 0.49
0.7 x 0.7 = 0.7^2

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3 years ago

Calculate the side lengths a and b to two decimal places.

Zinaida [17]

Answer:

$a=10.92 units$

$b=14.51 units$

Step-by-step explanation:

We are given that c=6 units

$\angle A=43^{\circ}$

$\angle B=115^{\circ}$

We have to find the side length a and b.

We know that sum of angles of a triangle =180 degrees

$\angle A+\angle B+\angle C=180$

Substitute the values then we get

$43+115+\angle C=180$

$158+\angle C=180$

$\angle C=180-158=22^{\circ}$

sine law: $\frac{a}{sin A}=\frac{b}{sin B}=\frac{c}{sin C}$

$\frac{a}{sin 43^{\circ}}=\frac{6}{sin 22^{\circ}}$

$a=\frac{6}{sin 22^{\circ}}\times sin 43^{\circ}$

$a=10.92 units$

$\frac{b}{sin 115^{\circ}}=\frac{6}{sin 22^{\circ}}$

$b=\frac{6}{sin 22^{\circ}}\times sin 115^{\circ}=14.51$

$b=14.51 units$

6 0

3 years ago

Find an equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4

Alina [70]

equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)

Perpendicular bisector lies at the midpoint of a line

Lets find mid point of (-9,-8) and (7,-4)

midpoint formula is

$\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}$

$\frac{-9+7}{2} ,\frac{-8+-4}{2}$

midpoint is (-1, -6)

Now find the slope of the given line

(-9,-8) and (7,-4)

$slope = \frac{y2-y1}{x2-x1} = \frac{-4-(-8)}{7-(-9)}$

$slope = \frac{-4+8}{7+9}= \frac{4}{16} =\frac{1}{4}$

Slope of perpendicular line is negative reciprocal of slope of given line

So slope of perpendicular line is -4

slope = -4 and midpoint is (-1,-6)

y - y1 = m(x-x1)

y - (-6) = -4(x-(-1))

y + 6 = -4(x+1)

y + 6 = -4x -4

Subtract 6 on both sides

y = -4x -4-6

y= -4x -10

equation for the perpendicular Bisector y = -4x - 10

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3 years ago

The midpoint of is M(4,-3) One endpoint is G(-2,2). find the coordinates of end point

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The other endpoint is (10, -8

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2 years ago

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Answer:

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