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ivolga24 [154]
3 years ago
15

The captain of a boat knows that a lighthouse on the coast is 100 ft. tall. If he measures the angle of elevation to be 2 degree

s, how far is the boat from the shore?
Mathematics
1 answer:
faltersainse [42]3 years ago
6 0

Answer and Step-by-step explanation:

           | \

           |   \

           |      \

           |         \

           |            \

100 ft.  |              \

           |         2     \

           |_________\

                    x

Use tangent to find the x.

tan(2) = \frac{100}{x}

x = \frac{100}{tan(2)}

Use a calculator to evaluate.

x = \frac{100}{tan(2)} = 2863.6253

So, the boat is 2,863.63 feet from the shore.

#teamtrees #WAP (Water And Plant)

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Solve for x 6x^2=2x-1
leva [86]

Answer:

\displaystyle x=\frac{1\pm i\sqrt{5}}{6}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

<u>Algebra II</u>

  • Imaginary Roots: √-1 = i

Step-by-step explanation:

<u>Step 1: Define</u>

6x² = 2x - 1

<u>Step 2: Rewrite</u>

  1. Subtract 2x on both sides:                    6x² - 2x = -1
  2. Add 1 to both sides:                               6x² - 2x + 1 = 0

<u>Step 3: Identify Variables</u>

a = 6

b = -2

c = 1

<u>Step 4: Solve for </u><em><u>x</u></em>

  1. Substitute [QF]:                       \displaystyle x=\frac{2\pm\sqrt{(-2)^2-4(6)(1)} }{2(6)}
  2. Exponents:                              \displaystyle x=\frac{2\pm\sqrt{4-4(6)(1)} }{2(6)}
  3. Multiplication:                         \displaystyle x=\frac{2\pm\sqrt{4-24} }{12}
  4. (Square Root) Subtract:         \displaystyle x=\frac{2\pm\sqrt{-20} }{12}
  5. Factor:                                    \displaystyle x=\frac{2\pm \sqrt{-1} \sqrt{20} }{12}
  6. Simplify:                                 \displaystyle x=\frac{2\pm 2i\sqrt{5} }{12}
  7. Factor GCF:                           \displaystyle x=\frac{2(1\pm i\sqrt{5} )}{12}
  8. Simplify:                                 \displaystyle x=\frac{1\pm i\sqrt{5}}{6}
3 0
3 years ago
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