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Andrew [12]
3 years ago
11

The length of a city’s bus routes are normally distributed with a mean of 14.5 mi and a standard deviation of 3.2 mi.

Mathematics
1 answer:
jeka57 [31]3 years ago
3 0
Thank you for posting your question here at brainly. Please see below answer:

a) What percentage of city bus routes are less than 15 mi? 
56.20820167 ≈ 56.2%

b)What percentage of city bus routes are greater than 20 mi? 
4.282995170  ≈ 4.3 %

c) What percentage of city bus routes are less than 10 mi?
<span>7.98 ≈ 7.98 %</span>
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Answer:

The number of cases of golf ball that team needed to raise money for equipment  is 3 .

Step-by-step explanation:

Given as :

The amount needed for new equipment = $850

The cost of each golf ball = $2

The number of packs of golf ball in each case = 24

The number of golf ball in each pack = 6

Let The number of cases of golf ball team needed to raise money for equipment = n cases

Now, According to question

∵ 1 pack has 6 balls

so, 24 pack has 6 × 24

i.e 24 packs has 144 balls

So, The number of balls in each case` = 144 balls

<u>Again</u>

∵ cost of 1 ball = $2

So, cost of 144 balls = $2 × 144

i.e cost of 144 balls in each case = $288

<u>Again</u>

∵ The amount needed for new equipment = $850

So, The number of cases of golf ball team needed to raise money for equipment = \dfrac{amount needed for new equipmen}{cost of 144 balls in each case }

Or, n = \dfrac{850}{288}

∴ n = 2.9 ≈ 3

So, The number of cases of golf ball that team needed to raise money for equipment  = n = 3

Hence, The number of cases of golf ball that team needed to raise money for equipment  is 3 . Answer

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Step-by-step explanation:

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The equation tan(55) = 15/b can be used to find the length of line AC.what is the length of line AC round to the nearest 10th 3.
Nadusha1986 [10]

Answer:

10.5 in

Step-by-step explanation:

Given

tan(55) = \frac{15}{b}

Required

Find length AC

The question is not detailed enough; so, I'll assume that b represents line AC.

Having said that;

We start by multiplying both sides by b

tan(55) = \frac{15}{b}

b * tan(55) = \frac{15}{b} * b

b * tan(55) =15

Divide both sides by tan(55)

\frac{b * tan(55)}{tan(55)} = \frac{15}{tan(55)}

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