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Andrew [12]
3 years ago
11

The length of a city’s bus routes are normally distributed with a mean of 14.5 mi and a standard deviation of 3.2 mi.

Mathematics
1 answer:
jeka57 [31]3 years ago
3 0
Thank you for posting your question here at brainly. Please see below answer:

a) What percentage of city bus routes are less than 15 mi? 
56.20820167 ≈ 56.2%

b)What percentage of city bus routes are greater than 20 mi? 
4.282995170  ≈ 4.3 %

c) What percentage of city bus routes are less than 10 mi?
<span>7.98 ≈ 7.98 %</span>
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3 - what = 11<br><br> please help with this one
SOVA2 [1]
So we can set up a simple equation for this, where the word “what” is a variable, x. This equation is 3 - x=11. Then we subtract 3 from both sides, giving us -x=8. We can divide both sides by -1, giving us x=-8. The answer would be -8. Hope this helped.
3 0
2 years ago
F(x)= -5x-1 and g(x)= 2x^2<br>solve (f+g)(x)
Georgia [21]
f(x)=-5x-1;\ D_f:x\in\mathbb{R}\\\\g(x)=2x^2;\ D_g:x\in\mathbb{R}\\\\D_f=D_g\ then\ (f+g)(x)=f(x)+g(x)\\\\(f+g)(x)=-5x-1+2x^2=2x^2-5x-1

8 0
3 years ago
Read 2 more answers
In 1924, the tempature in Fairfield, Montana, dropped from 63 degrees to 21 in 12 hour. What was the average hourly change in te
Drupady [299]
Find the change
the change is 63-21=42
42 degrees in 12 hours
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42/12=3.5 degrees per hour
8 0
3 years ago
PLEASE HELP ITS URGENT
Nataly [62]

Answer:

I don't believe this is a mathematics related question....

Step-by-step explanation:

Don't have someone write this for you though, this sounds like a fun assignment. If you need help with the terms

Central plot = what is happening. Is a king trying to fight off a dragon? A penguin trying to learn to hunt?

Conflict = what goes wrong to make the goal harder.

Conclusion = How it ends.

Characters = People or creatures in the story.

Dialogue = What people are saying.

Setting = When and where the story takes place.

7 0
2 years ago
See question in attached photo.​
statuscvo [17]

9514 1404 393

Answer:

  (a, b) = (-2, -1)

Step-by-step explanation:

The transpose of the given matrix is ...

  A^T=\left[\begin{array}{ccc}1&2&a\\2&1&2\\2&-2&b\end{array}\right]

Then the [3,1] term of the product is ...

  (A\cdot A^T)_{31}=\left[\begin{array}{ccc}a&2&b\end{array}\right]\cdot\left[\begin{array}{ccc}1&2&2\end{array}\right]=a+2b+4

and the [3,2] term is ...

  (A\cdot A^T)_{32}=\left[\begin{array}{ccc}a&2&b\end{array}\right]\cdot\left[\begin{array}{ccc}2&1&-2\end{array}\right]=2a-2b+2

Both of these terms in the product matrix are 0. We can solve the system of equations by adding these two terms:

  (a +2b +4) +(2a -2b +2) = (0) +(0)

  3a +6 = 0

  a = -2

Substituting for 'a' in term [3,1] gives ...

  -2 +2b +4 = 0

  b = -1

The ordered pair (a, b) is (-2, -1).

8 0
2 years ago
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