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2 years ago

What is definition of and INDEPENDENT Vairable?

Mathematics

2 answers:

tangare [24]2 years ago

6 0

Answer:

a variable (often denoted by x) whose variation does not depend on that of another.

Step-by-step explanation:

Ilya [14]2 years ago

3 0

Answer:

An independent variable is exactly what it sounds like. It is a variable that stands alone and isn't changed by the other variables you are trying to measure. For example, someone's age might be an independent variable.

You might be interested in

What does this mean -(-c) when c+2/3 on the numberline

ad-work [718]

Answer:

Step-by-step explanation:

a negative minus a negative is a positive so it mean c plus 2divided by 3 on the the number line

5 0

3 years ago

Juans three math quizzes this week took him 1/3?4/6?and1/5 hour to complete. List all the fraction from least to greatest

Alex

Answer:

$\frac{1}{5}$ , $\frac{1}{3}$ , $\frac{4}{6}$ .

Step-by-step explanation:

Given fractions $\frac{1}{3}$ , $\frac{4}{6}$ , $\frac{1}{5}$ .

We need to list them from least to greatest.

In order to arrange them from least to greatest, we need to find the least common denominator of $\frac{1}{3}$ , $\frac{4}{6}$ , $\frac{1}{5}$ .

We have 3, 6 and 5 in denominators.

Least common multiple of 3, 6 and 5 is = 30, because 30 is least number that can be divided by all three number 3, 6 and 5.

Let us covert each denominator as 30.

Multiplying first fraction $\frac{1}{3}$ by 10 in top and bottom, we get

$\frac{1}{3} = \frac{1\times10}{3\times10}=\frac{10}{30}$

Multiplying first fraction $\frac{4}{6}$ by 5 in top and bottom, we get

$\frac{4}{6} = \frac{4\times5}{6\times5}=\frac{20}{30}$

Multiplying first fraction $\frac{1}{5}$ by 6 in top and bottom, we get

$\frac{1}{5} = \frac{1\times6}{5\times6}=\frac{6}{30}.$

Now, we can check $\frac{10}{30}, \frac{20}{30} \ and \ \frac{6}{30}.$

$\frac{6}{30}$ is the smallest, $\frac{10}{30}$ is greater and $\frac{20}{30}$ is the greatest.

Therefore, we can arrange fractions $\frac{6}{30}, \frac{10}{30} \ and \ \frac{20}{30}.$

Writing original fractions in place of equivalent fractions, we can write

$\frac{1}{5}$ , $\frac{1}{3}$ and $\frac{4}{6}$ .

Therefore, the order the amounts of paint from least to greatest is:

$\frac{1}{5}$ , $\frac{1}{3}$ , $\frac{4}{6}$ .

4 0

2 years ago

Can someone help me with this thanks

Ugo [173]

The length of the brace required is 4.3m

What is sine rule?

In a ΔABC a, b and c are the sides and A, B and C are angles then,

$\frac{a}{SinA}=\frac{b}{sinB}=\frac{c}{sinC}$

We can find the length, l as shown below:

Let AB=3m, BC=2m and AC=l

Let ∠A=25°

So, in ΔABC

$\frac{BC}{sinA}=\frac{AB}{sinC}=\frac{AC}{SinB}$

$\frac{BC}{sinA}=\frac{AB}{sinC}$

$\frac{2}{sin25}=\frac{3}{sinC}$

$\angle{C}=sin^{-1}(\frac{3\times sin25}{2} )$

∠C=39.34°

∠A+∠B+∠C=180°

∠B=180°-25°-39.34°

∠B=115.66°

$\frac{BC}{sinA}=\frac{AC}{SinB}$

$\frac{2}{sin25}=\frac{l}{sin(115.66)}$

$l=\frac{2\times sin(115.66)}{sin25}$

l=4.2659

Rounding to nearest tenth of meter.

l=4.3m

Hence, the length of the brace required is 4.3m

Learn more about Sine Rule here:

brainly.com/question/25852087

#SPJ1

8 0

1 year ago

A rectangular image of length 5 cm and width 7 cm is magnified in a studio. On magnification, 1 cm of the image represents 15cm.

Andre45 [30]

Answer:

238 cm

Step-by-step explanation:

so we have a scale factor of 17: 1

originally we had the dimensions: 3cm by 4m

now we have 3*17 by 4*17 = 51 cm by 68 cm

Perimeter = 2*51 + 2*68 = 238 cm

8 0

1 year ago

Read 2 more answers

find the equations of the tangents to the curve y= x(x-1)(x+2) at the points where the curve cuts the x axis

antoniya [11.8K]

First of all, we compute the points of interest, i.e. the points where the curve cuts the x axis: since the expression is already factored, we have

$x(x-1)(x+2) = 0 \iff x=0\ \lor\ x-1=0\ \lor\ x+2=0$

Which means that the roots are

$x=0\ \lor\ x=1\ \lor\ x=-2$

Next, we can expand the function definition:

$y = x(x-1)(x+2) = x^3 + x^2 - 2x$

In this form, it is much easier to compute the derivative:

$y' = 3x^2+2x-2$

If we evaluate the derivative in the points of interest, we have

$y'(-2) = 6,\quad y'(0)=-2,\quad y'(1)=3$

This means that we are looking for the equations of three lines, of which we know a point and the slope. The equation

$y-y_0=m(x-x_0)$

is what we need. The three lines are:

$y-0=6(x+2) \iff y = 6x+12$ This is the tangent at x = -2

$y-0=-2(x-0) \iff y = -2x$ This is the tangent at x = 0

$y-0=3(x-1) \iff y = 3x-3$ This is the tangent at x = 1

7 0

2 years ago