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3 years ago

(A) all values at which F has a local maximum: (B) all local maximum values of F:

Mathematics

1 answer:

Bingel [31]3 years ago

6 0

Answer:

(a) {-3, 2}

(b) {3, 4}

Step-by-step explanation:

The high points are (-3, 3) and (2, 4).

The x-values at which the function has a local maximum are {-3, 2}.

The local maximum values are {3, 4}.

_____

Your answer box probably doesn't want the curly brackets and maybe not the spaces, either. Those brackets are used to identify a <em>set</em> of values.

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What values of a and b make the equation true? StartRoot 648 EndRoot = StartRoot 2 Superscript a Baseline times 3 Superscript b

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Option C: $a=3, b=4$ is the value of a and b

Explanation:

Given that the expression $\sqrt{648}=\sqrt{2^a\times3^b}$

We need to determine the value of a and b

Let us consider the term $\sqrt{648}$ and take the prime factorization of the term 648

Thus, we have,

648 divides by 2,

$648=2 \cdot 324$

324 divides by 2,

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$648=2 \cdot 2 \cdot 2 \cdot 81$

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$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 3 \cdot 3$

Thus, we have,

$\sqrt{648}=\sqrt{2^{3} \cdot 3^{4}}$

Therefore, equating the powers of 2 and 3, we get,

$a=3, b=4$

Hence, the value of a and b is 3 and 4

Thus, Option C is the correct answer.

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