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zhuklara [117]
3 years ago
7

Solve for y. y – (–19) = 25 a. –44 b. –6 c. 6 d. 44

Mathematics
1 answer:
babymother [125]3 years ago
6 0
Y - (-19) = 25

First, simplify your brackets. / Your problem should look like: y + 19 = 25
Second, subtract 19 from both sides. / Your problem should look like: y = 25 - 19
Third, subtract 25 - 19 to get 6. / Your problem should look like: y = 6

Answer: C) y = 6

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Is 1 4/5 greater than or less than 9 and why
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The quadratic formula gives which roots for the equation 2x^2 + x - 6 = 0?
Jet001 [13]

Answer:

The roots are x = (\frac{3}{2}, -2), which is given by option C.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question, we have that:

2x^2 + x - 6 = 0

Which is a quadratic equation with a = 2, b = 1, c = -6. So

\Delta = 1^{2} - 4*2(-6) = 1 + 48 = 49

x_{1} = \frac{-1 + \sqrt{49}}{2*2} = \frac{6}{4} = \frac{3}{2}

x_{2} = \frac{-1 - \sqrt{49}}{2*2} = \frac{-8}{4} = -2

So the roots are x = (\frac{3}{2}, -2), which is given by option C.

3 0
3 years ago
Solve -2t + 5 ≥ -7.<br><br> A. t ≤ 6<br> B. t ≤ -6<br> C. t ≥ 6<br> D. t ≥ -6
TiliK225 [7]
A.t is less than or equal to 6
7 0
3 years ago
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50 POINTS PLEASE HELP
Leni [432]

Answer: 2nd step

Step-by-step explanation:

(-4s+5 )/-4 ≥ 16/-4

S-(5/4) ≥ -4

S ≥ -4+(5/4)

S ≥ 1/4

8 0
3 years ago
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