Question

The base of a triangle is twice its hypotenuse, the sine of the angle opposite to its base is

Answer 1

Answer:

Option (c) is correct .

The base of a triangle is twice its hypotenuse, the sine of the angle opposite to its base is $=\frac{1}{2}$

Step-by-step explanation:

Given : base =  twice its hypotenuse

that is ,

Consider hypotenuse  be x  then base will be 2x .

Consider the right angled triangle in figure below with right angle at B and base BC.

∠A is the angle opposite to the base.

$\text sinA=\frac{\text Perpendicular}{\text Hypotenuse}$

$\text sinA=\frac{BC}{AC}$

$\text sinA=\frac{x}{2x}$

$\text sinA=\frac{1}{2}$

Thus, For the base of a triangle is twice its hypotenuse, the sine of the angle opposite to its base is $=\frac{1}{2}$

Answer 2

The answer   b= 2h
the angle  opposite to its base is a
so sina = b/2h= b/b=1
the answer is b) 1