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Trava [24]
3 years ago
13

The base of a triangle is twice its hypotenuse, the sine of the angle opposite to its base is

Mathematics
2 answers:
agasfer [191]3 years ago
8 0

Answer:

Option (c) is correct .

The base of a triangle is twice its hypotenuse, the sine of the angle opposite to its base is =\frac{1}{2}

Step-by-step explanation:

Given : base =  twice its hypotenuse

that is ,

Consider hypotenuse  be x  then base will be 2x .

Consider the right angled triangle in figure below with right angle at B and base BC.

∠A is the angle opposite to the base.

\text sinA=\frac{\text Perpendicular}{\text Hypotenuse}

\text sinA=\frac{BC}{AC}

\text sinA=\frac{x}{2x}

\text sinA=\frac{1}{2}

Thus, For the base of a triangle is twice its hypotenuse, the sine of the angle opposite to its base is =\frac{1}{2}












svetoff [14.1K]3 years ago
6 0
The answer   b= 2h
the angle  opposite to its base is a
so sina = b/2h= b/b=1
the answer is <span>b) 1</span>
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