A dice cube has 6 sides that are numbered 1 to 6. If the cube is thrown once, what is the probability of rolling an odd number?

The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe

UNO [17]

Answer:

The shark are fed $\frac16 \ ton$ of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = $\frac{2}{15}\ ton$

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = $\frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton$

Total fish fed in whole day = $\frac12 \ ton$

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = $\frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}$

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = $\frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}$

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = $\frac{3-2}{6}=\frac16 \ ton$

Hence The shark are fed $\frac16 \ ton$ of fish during the night.

3 0

3 years ago

Sarah is saving money to buy a microscope. She has saved $25 so far. That's 1/3 of the

seropon [69]

Answer:

X = $75

Step-by-step explanation:

X=total cost

x* (1/3) =$25

multiply by 3 on both sides

x=$75

4 0

3 years ago

The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016

hodyreva [135]

Answer:

Required Probability = 0.97062

Step-by-step explanation:

We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.

Let X = weight of the newborn baby, so X ~ N( $\mu=4016 , \sigma^{2} = 532^{2}$ )

The standard normal z distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Now, probability that the weight will be less than 5026 grams = P(X < 5026)

P(X < 5026) = P( $\frac{X-\mu}{\sigma}$ < $\frac{5026-4016}{532}$ ) = P(Z < 1.89) = 0.97062

Therefore, the probability that the weight will be less than 5026 grams is 0.97062 .

5 0

3 years ago

Mark has $16 to buy lunch for himself and his sister. He wants to buy at least one sandwich and one bag of chips. Sandwiches cos

faltersainse [42]

Answer:

Victor runs a small sandwich shop. He decides to start offering bags of chips to his customers. He finds a supplier where he can buy chips for $0.30 per bag. Victor needs to determine how much to charge for the chips at his shop. He does some research by talking to other nearby sandwich shop owners. The table below shows their sales per week for two different prices. (The values are: 150 bags sold, for $1.00 per bag, and 350 bags sold, for $0.50 per bag.) Victor believes that there is a linear relationship between the number of bags sold and the price. Victor wants to price the bags of chips so that he will maximize his profits. Determine the price Victor should charge for a bag of chips. Use the equation P(x)=R(x)-C(x), where P(x) represents profit, R(x) represents revenue, and C(x) represents cost. Each is a function of the number of bags of chips sold, x. Round your answer to the nearest nickel.

Step-by-step explanation:

Victor runs a small sandwich shop. He decides to start offering bags of chips to his customers. He finds a supplier where he can buy chips for $0.30 per bag. Victor needs to determine how much to charge for the chips at his shop. He does some research by talking to other nearby sandwich shop owners. The table below shows their sales per week for two different prices. (The values are: 150 bags sold, for $1.00 per bag, and 350 bags sold, for $0.50 per bag.) Victor believes that there is a linear relationship between the number of bags sold and the price. Victor wants to price the bags of chips so that he will maximize his profits. Determine the price Victor should charge for a bag of chips. Use the equation P(x)=R(x)-C(x), where P(x) represents profit, R(x) represents revenue, and C(x) represents cost. Each is a function of the number of bags of chips sold, x. Round your answer to the nearest nickel.

4 0

3 years ago

Solve - pv + 40 < 65 for v<br> solve 7w - 3r = 15 for r

Katarina [22]

Answer:

v > -25/p

r = -5 +7/3 w

Step-by-step explanation:

- pv + 40 < 65

Subtract 40 from each side

- pv + 40-40 < 65-40

-pv < 25

Divide each side by -p (remember to flip the inequality since we are dividing by a negative)

-pv/-p > 25/-p

v > -25/p

7w - 3r = 15

Subtract 7w from each side

7w-7w - 3r = 15-7w

-3r = 15-7w

Divide by -3

-3r/-3 = (15-7w)/-3

r = -5 +7/3 w

8 0

3 years ago