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mafiozo [28]
3 years ago
15

You lose one quarter, 2 dimes, and 2 nickels

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
8 0
.25+.10+.10+.05+.05=0.55
fraction:55/100
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Cot y, if csc y =-10/3 and cos y< 0
fredd [130]
\csc y=-\dfrac{10}3\implies\sin y=-\dfrac3{10}

\cos^2y=1-\sin^2y\implies \cos y=\pm\sqrt{1-\dfrac9{100}}=\pm\dfrac{\sqrt{91}}{10}

You're told that \cos y, so omit the positive root.

\cot y=\dfrac{\cos y}{\sin y}=\dfrac{-\frac{\sqrt{91}}{10}}{-\frac3{10}}=\dfrac{\sqrt{91}}3
7 0
3 years ago
Find m∠TUL.
pogonyaev

 

Step-by-step explanation:

Actual graph for this problem is attached below

m∠TUV = 167°

m∠TUL = (x + 11)°

m∠LUV = (11x)°

m∠TUV= m∠TUL+ m∠LUV

now plug in the angles for each

m∠TUV= m∠TUL+ m∠LUV

167= x+11 +11x

solve the equation for x

167= x+11 +11x\\167=11 +12x

Subtract 11 from both sides

156=12x

divide both sides by 12

x=13

m∠TUL = (x + 11)°

m∠TUL = (13+ 11)° = (24)°

answer:

24°

4 0
3 years ago
How many adult tickets were sold if each adult ticket sold was $6 and each student ticket was $4.50 and 260 tickets were sold fo
erik [133]

Answer:

   Adult tickets sold:   156

Step-by-step explanation:

   Adult ticket:   x

Student ticket:  y

x + y = 260                  ===>   -6(x + y = 260)     ===>  -6x -6y = -1560

6x + 4.5y = 1404         ===>                                           6x + 4.5y = 1404

                                                                                  ________________

add the two equations to eliminate a variable:                  -1.5y = -156

divide by -1.5:                                                                              y = 104

substitution to find x:

      x + y = 260

  x + 104 = 260

            x = 156

5 0
3 years ago
I need to know the answer to the question with the circle
KATRIN_1 [288]
___________________________

◆ AREA RELATED TO CIRCLES ◆ ___________________________

As shown in the figure ,

Radius of circle = 5 cm

Side of square = 2 × (Radius of inscribed circle)

Side of square = 2 × 5 cm

Side of square = 10 cm = a

___________________________

Now ,
Area of shaded region = (Area of square) - ( Area of inscribed circle )

Area of shaded region =
{a}^{2} - \pi {r}^{2}

Area of shaded region =
{10}^{2} - \frac{22}{7} \times {5}^{2}

Area of shaded region = 100 - 78.571

= 21.428 \: ans.

7 0
3 years ago
Diego measured the length of a pen to be 22 cm. The actual length of the pen is 23 cm
jeyben [28]

Answer:a

Step-by-step explanation:

5 0
3 years ago
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