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nirvana33 [79]
3 years ago
7

HELP ASAP PLEASE!!!! EXTRA POINTS!!

Mathematics
1 answer:
uysha [10]3 years ago
8 0
The answers are A, B, and D because to find the percent, you would have to multiply the percent by the number you're trying to get out of. There are different but correct ways written in A, B, and D.
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What is the algebraic expression for the word phrase “the quotient of 18 and 9 less than a”?
sammy [17]
The answer to the question above is option D: <span>18/ 9-a. If we try to analyze the word phrase above, this is the algebraic expression that matches it. When we say quotient, this is the number or the result of the division between two numbers. So the quotient of 18 and 9, this means that the answer of 18 divided by 9. And then, less than a. Less than a here means subtraction or minus. Therefore, this makes -a. </span>
7 0
3 years ago
Determine if the two triangles are congruent.If they are state how you know
Finger [1]

Answer:

1. yes, both triangles sides are congruent

2. yes, they have congruent sides and they have a congruent angle

3. yes, congruent sides and angle

4. yes, 2 congruent angles

5. no, only one congruent angle not enough proof

6. yes, 2 congruent angles

7. no, only one congruent angle not enough proof

8. no, only one congruent side

6 0
2 years ago
Read 2 more answers
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
Korolek [52]

Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this question, we have that:

\pi = 0.21

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.21*0.79}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.21*0.79}

\sqrt{n} = \frac{1.645\sqrt{0.21*0.79}}{0.03}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.21*0.79}}{0.03})^2

n = 498.81

Rounding up

A sample of 499 is needed.

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2 years ago
(a + b)(a – b) = a2 + b2 true or false?
Alja [10]
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