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3 years ago

How could you use compensation to find 391-26

Mathematics

1 answer:

almond37 [142]3 years ago

7 0

This equals 365 i know that is not what you ask but this is what i know

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Wendy has $27 to buy seed for her birdfeeders. Each bag of seed costs $5.

Alekssandra [29.7K]

Answer:

Step-by-step explanation:

If Wendy has $27 to buy seeds, and each seed bag costs $5, then:

5 · 5 = 25

5 · 6 = 30

27<30

27>25

So, Wendy is able to buy 5 bags and remain with 2 dollars.

5 0

2 years ago

Read 2 more answers

ITS URGENT PLEASE HELP Which equation represents the line that is parallel to y=3/7x+11 and passes through (-21,42)?

Pepsi [2]

Answer:

y = 3/7x + 51

Step-by-step explanation:

y = 3/7x + 11 is parallel to the line so it means that both of their gradient are same so:

y = mx + c

m= gradient point = (-21 , 42)

= 3/7

now we sub the m and the point into the formula which is y= mx+c because we should find the c first then we can find the equation of the line:

42 = 3/7 (-21) + c

42 = -9 + c

42 + 9 = c

51 = c

c = 51

now you hv to rewrite again the equation become y= 3/7x + 51

So now your final answer is : y = 3/7x +51

3 0

3 years ago

Measure Math | Welcome, HAILEE KNOTT

grandymaker [24]

Answer: $15\times\frac{1}{2}$

Explanation:

Multiplying by 1/2 is the same as dividing by 2.

For example, if you have 10 slices of cake and 2 friends, then each friend gets 10/2 = 5 slices. We could also say $10\times \frac{1}{2} = 5$

The fraction 1/2 converts to the decimal form 0.5, which means $10 \times \frac{1}{2} = 10*0.5$

3 0

3 years ago

Can you please help me

alexandr402 [8]

Answer:

$D$

Step-by-step explanation:

Every integer is a rational number.

8 0

3 years ago

What is wrong with the following equation?x2+xâˆ’20/xâˆ’4=x+5a. (xâˆ’4)(xâˆ’5)â‰ x2+xâˆ’20b. The left-hand side is not defined f

joja [24]

Answer:

The answer to this question can be defined as follows:

In part (i), the answer is "option d".

In part (ii), the answer is "option 2".

Step-by-step explanation:

Given:

Part (a)

$\Rightarrow \bold{\frac{x^2+x-20}{x-4}=x+5}\\\\$

Solve the above equation:

$\Rightarrow x^2+x-20=(x+5)(x-4)\\\\\Rightarrow x^2+x-20=(x^2-4x+5x-20)\\\\\Rightarrow x^2+x-20=x^2-4x+5x-20\\\\\Rightarrow \boxed{x^2+x-20=x^2+x-20}\\$

Given:

Part (b)

$\Rightarrow \bold{ \lim_{x \to \3} \frac{x^2+x-12}{x-3}= \lim_{x \to 3} (x+4)}\\\\$

Solve the above equation:

factor of $\Rightarrow x^2+x-20 =(x-3)(x+4)$

$\Rightarrow \lim_{x \to \3} \frac{(x-3)(x+4)}{x-3}= \lim_{x \to 3} (x+4)\\\\\Rightarrow \lim_{x \to \3} (x+4)= \lim_{x \to 3} (x+4)\\\\$

apply limit value:

$\Rightarrow (3+4)= (3+4)\\\\\Rightarrow 7= 7$

6 0

3 years ago