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Pani-rosa [81]
3 years ago
9

normally distributed with an unknown population mean and a population standard deviation of 4.5 points. A random sample of 45 sc

ores is taken and gives a sample mean of 84. Find a 90% confidence interval
Mathematics
1 answer:
shusha [124]3 years ago
3 0

Answer:

= ( 82.90, 85.10) points

Therefore at 90% confidence interval (a,b)= ( 82.90, 85.10) points

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 84

Standard deviation r = 4.5

Number of samples n = 45

Confidence interval = 90%

z(at 90% confidence) = 1.645

Substituting the values we have;

84+/-1.645(4.5/√45)

84+/-1.645(0.670820393249)

84+/-1.10

= ( 82.90, 85.10) points

Therefore at 90% confidence interval (a,b)= ( 82.90, 85.10) points

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Answer quickly please.
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Answer:

8.333333

Step-by-step explanation:

 3x+2(4+6x)=133

  3x+8+12x=133                      First I distibuted the 2 too the 4 and 6x

15x+8=133                                 Then I added the x es 3x and 12x

15x+8-8=133-8                         Then I subracted 8 from both sides

15x=125                                    That leaves with this

 15x/15=125/15                          Now I divide 15 from both sides to isolate x

x= 8.33333                                 that is the answer

                             check

                  3x+2(4+6x)=133

                 3*8.333333+2(4+6*8.333333)=133

                  24.999999 +2(4+ 49.999998)=133

                    24.999999+2( 53.999998)=133

                         24.999999+107.999996=133

                              132.999995=133

                       

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