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3 years ago

I need to divide a recipe in half that calls for 1/2 of a cup of sugar. How much sugar do I need?

Mathematics

2 answers:

pochemuha3 years ago

8 0

Answer:1/4

Step-by-step explanation:

1/2 divided by 2 = 1/4

ella [17]3 years ago

3 0

Answer:

1/4 cup of sugar

Step-by-step explanation:

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Graph the solution of −5a+6>11.<br> Please, I need help!!!

horsena [70]

Answer:

$\large\boxed{a$

Step-by-step explanation:

$-5a+6>11\qquad\text{subtract 6 from both sides}\\\\-5a>5\qquad\text{change the signs}\\\\5a$

4 0

3 years ago

Evaluate the following function: Show all work! h(x)=3x²+2-2x, Find h(-2)

Mkey [24]

<h2><u>Polynomial Function</u></h2>

<h3>Evaluate the following function: Show all work! h(x)=3x²+2-2x, Find h(-2)</h3>

To determine the answer, substitute the given value to the function and simplify.

h(x) = 3x² + 2 - 2x; h(-2)
h(-2) = 3(-2)² + 2 - 2(-2)
h(-2) = 3(4) + 2 + 4
h(-2) = 12 + 2 + 4
h(-2) = 14 + 4
h(-2) = 18

<u>Answer:</u>

<u>18</u> is the answer.

Wxndy~~

8 0

2 years ago

I BEG U HELP ME!! Does each equation represent exponential decay or exponential growth?

ivolga24 [154]

Answer:

see below

Step-by-step explanation:

If the base of the exponential term is greater than 1, it represents growth.

If the base of the exponential term is less than 1, it represent decay.

If there is no exponential term, the characterization as exponential growth or decay does not apply.

8 0

3 years ago

When calculating the area of a trapezoid how do you determine which sides are the bases

Evgesh-ka [11]

The "bases" are the two sides of the trapezoid that are parallel.

7 0

3 years ago

Use a(t) = −9.8 meters per second per second as the acceleration due to gravity. (Neglect air resistance.) A canyon is 2100 mete

Umnica [9.8K]

Answer:

$t \approx 20.7\,s$

Step-by-step explanation:

Given that rock experiments a constant acceleration, position function can be obtained by integrating twice:

$v(t) = v_{o} - a\cdot t$

$s(t) = s_{o} + v_{o}\cdot t -\frac{a}{2}\cdot t^{2}$

The initial conditions of the rock are, respectively:

$s_{o} = 2100\,m$

$v_{o} = 0\,\frac{m}{s}$

Position of the rock as a function of time is:

$s(t) = 2100\,m -(4.9\,\frac{m}{s^{2}})\cdot t^{2}$

The time taken for the rock to hit the canyon floor is:

$0\,m = 2100\,m - (4.9\,\frac{m}{s^{2}} )\cdot t^{2}$

$2100\,m = (4.9\,\frac{m}{s^{2}} )\cdot t^{2}$

$t = \sqrt{\frac{2100\,m}{4.9\,\frac{m}{s^{2}} } }$

$t \approx 20.7\,s$

8 0

3 years ago