X-intercepts are points where the graph intersects the x-axis, i.e. when y=0.
Substitute y=0 and solve for x:
y=x^2-3x+2
0=x^2-3x+2
0=(x-2)(x-1)
By the zero product property, we deduce x-2=0 or x-1=0, i.e. x=1 or x=2.
This is a division problem. First, get 12 1/3 into fraction form instead of mixed number form to make your life easier;
Now, divide the two fractions. Since this is fraction division, the reciprocal is flipped and the two fractions multiplied.
The answer from the fraction division is 16 and four-ninths, but because you need a whole number as an answer,
the answer is 16 pieces.
Area of semicircle = 1/2 the area of a circle:

radius is half the diameter of 6ft.

Area of the rectangle:

Add the two together:
90 + 14.13 = 104.13
Round to the nearest tenth (one decimal place)
Area = 104.1 square feet.
Question..
Combine like terms to create an equivalent expression.
½ −⅙q +⅚q - ⅓
Answer:
½ −⅙q +⅚q - ⅓ is equivalent to ⅔q + ⅙
Step-by-step explanation:
Given
½ −⅙q +⅚q - ⅓
Required
Equivalence
½ −⅙q +⅚q - ⅓
We start by collecting like terms.
⅚q - ⅙q + ½ - ⅓
Factorize
(⅚ - ⅙)q + ½ - ⅓
((5 - 1)/6)q + ½ - ⅓
(4/6)q + ½ - ⅓
Reduce 4/6 to lowest term
⅔q + ½ - ⅓
Evaluate fraction
⅔q + (3 - 2)/6
⅔q + ⅙
Hence, ½ −⅙q +⅚q - ⅓ is equivalent to ⅔q + ⅙
<h2>The cost is same for both the options if we purchase 27 photos</h2>
Step-by-step explanation:
Cost of a photo at a local store is $0.25 per photo. This cost can be modeled to be linear in number of photos as
.
Cost of photos purchased online is $0.15 per photo. However there is a shipping cost of $2.70. This can also be modeled to be linear in number of photos as
.
Let us assume both costs are the same if we purchase
photos.
So, 



∴ On purchasing 27 photos, cost for both the options is the same.