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ehidna [41]
3 years ago
10

How are the cummutative property of addition and the commutative property of multiplication aloke

Mathematics
1 answer:
vaieri [72.5K]3 years ago
7 0
They both switch around numbers 
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You find your dependent variable has a high degree of kurtosis. What is the first way to try to fix it?
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The first way to try to fix this is to apply logarithm to the observations on the dependent variable. This is going to make the dependent variable with high degree of kurtosis normal.

Note that sometimes, the resulting values of the variable will be negative. Do not worry about this, as it is not a problem. It does not affect the regression coefficients, it only affects the regression intercept, which after transformation, will be of no interest.

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Use the point P(3, —6). Write the ordered pair for the final location of the given point after completing the transformations in
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6 0
2 years ago
50 POINTS WILL GIVE BRAINIEST. Which of the following numbers are irrational?
Otrada [13]

Answer:

\sf \dfrac{\pi}{3}\:\:and\:\:\sqrt[\sf 3]{\sf 25}

Step-by-step explanation:

<u>Definitions</u>

Integer: A whole number that can be positive, negative, or zero.

Rational Number: A number that can be expressed as the ratio of two integers (where the denominator does not equal zero).

Irrational Number: A real number that <u>cannot</u> be written as a rational number.

\sf -8.2183 \times 10000=-82183

\implies \sf -8.2183=-\dfrac{82183}{10000}

Therefore, -8.2183 can be expressed as a <u>rational number</u>.

π is an <u>infinite decimal</u>, so it cannot be expressed as a rational number.  

\textsf{Therefore},\:\dfrac{\pi}{3}\:\textsf{is irrational}.

\sqrt[\sf 3]{\sf 25} is an irrational number.

\sf 9+ \sqrt{4}=9+\sqrt{2^2}=9+2=11

As 11 can be expressed as ¹¹/₁ then 9 + √4 is <u>rational</u>.

<u>Conclusion</u>

Therefore, the numbers that are irrational are:

\sf \dfrac{\pi}{3}\:\:and\:\:\sqrt[\sf 3]{\sf 25}

8 0
1 year ago
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