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ss7ja [257]
4 years ago
15

No asking bc I have most of it myself but helping would be great

Mathematics
1 answer:
trapecia [35]4 years ago
8 0

Answer:

pretty sure its 3

Step-by-step explanation:

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What formula to use <br> Answer
77julia77 [94]

Check the picture below.

now, since we know what "f" is, let us use the CNT triangle with the small COR one.


\bf \cfrac{36+f+30}{36}=\cfrac{48+32+g}{48}\implies \cfrac{36+24+30}{36}=\cfrac{48+32+g}{48} \\\\\\ \cfrac{90}{36}=\cfrac{80+g}{48}\implies \cfrac{5}{2}=\cfrac{80+g}{48}\implies 240=160+2g \\\\\\ 80=2g\implies \cfrac{80}{2}=g\implies 40=g

4 0
4 years ago
Consider the probability that more than 87 out of 155 students will pass their college placement exams. Assume the probability t
Helen [10]

the probability that more than 87 students will pass their college placement exam is 0.9616.

5 0
4 years ago
Sara has 24 sweets
Tresset [83]
<h2>Hello!</h2>

The answer is:

The expression for the number of sweets that Sara and Tim have now, are:

Sara=(17-x)Sweets\\\\Tim=\frac{(24+x)Sweets}{2}

<h2>Why?</h2>

To write the expressions for the number of sweets that Sara and Tim have now, we need to follow the next steps:

Sara starts with 24 sweets and Tim starts with 24 sweets

Sara=24 Sweets\\Tim=24 Sweets

Then, Sara gives Tim x Sweets

Sara=(24-x)Sweets\\Tim=(24+x)Sweets

Then. Sara eats 7 of her Sweets

Sara=(24-x-7) Sweets\\Sara=(17-x )Sweets\\Tim=(24+x) Sweets

Then, Tim eats half of his sweets

Sara=(17-x)Sweets\\\\Tim=\frac{(24+x)Sweets}{2}

So, the expression for the number of sweets that Sara and Tim have now, are:

Sara=(17-x) Sweets\\\\Tim=\frac{(24+x)Sweets}{2}

Have a nice day!

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4 years ago
Order from smallest to greatest <br><br> urgent !
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1 year ago
Determine whether the improper integral converges or diverges, and find the value of each that converges.
pantera1 [17]

Answer:

It diverges.

Step-by-step explanation:

We are given the integral: \int\limits^{-1}_{-\infty} \ln |x| dx

\int\limits^{-1}_{-\infty} \ln |x| dx=\int\limits^{-1}_{-\infty} \ln (-x) dx=\\\\= \lim_{t \to \infty} \int\limits^{-1}_{-t} \ln (-x) dx= \lim_{t \to \infty}( x(\ln \left(-x\right)-1))|^{-1}_{-t}=1-\infty=-\infty

So it is divergent.

7 0
4 years ago
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