Answer:
second option
Step-by-step explanation:
x - y= 28
x+y = 56
The number of birthday cards made is 72.
<h3>Description of ratios</h3>
Ratio expresses the relationship between two numbers. It shows the frequency of the number of times that one value is contained in another number. The sign used to represent ratios is :
<h3>Determining the total cards made. </h3>
Total card = (sum of ratios x number of get well cards) / ratio of get well cards
(11 x 60) / 5 = 132
<h3>Number of birthday cards made </h3>
6/11 x 132 = 72 cards
To learn more about ratios, please check: brainly.com/question/25927869
4, 9, 16, 25, 36, 49, 64, 81, 100, 121
a negative times a negative is a positive and squaring those numbers would be multiplying a negative by itself.
For example (-2)*(-2) is 4
**note, this only applies if the negative value is in the parentheses. (-2)^2 is different than -2^2 because with -2^2 only the 2 is getting squared and then you’d have to multiply the negative after**
Answer:
The answer is:

Step-by-step explanation:

First, we have to make the denorminator same by multiplying:


Then, we can add up everything together:


(Sorry if being messy)