There are two <em>real</em> roots for the <em>quadratic</em> equation x² - 8 · x + 13 = 0, contained in the number x = 4 ± √2.
<h3>How to find the roots of a polynomial by completing the square</h3>
In this question we must apply algebraic handling to simplify a <em>quadratic</em> equation and find the roots that satisfy the expression. Completing the square consists in transforming part of the equation into a <em>perfect square</em> trinomial, and then we clear for x:
x² - 8 · x + 13 = 0
x² - 8 · x + 16 = 3
(x - 4)² = 3
x - 4 = ± √2
x = 4 ± √2
There are two <em>real</em> roots for the <em>quadratic</em> equation x² - 8 · x + 13 = 0, contained in the number x = 4 ± √2.
To learn more on quadratic equations: brainly.com/question/2263981
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Yes. If the side lengths are different, you can end up with different angle measurements (example: SSA~ property. You can have two sides that are the same but you can make two different triangles with those side lengths and that one angle.)
The traveling time would be 470,588.235294km/hr
Step-by-step explanation:
I assume AB is supposed to be a straight line. yes ?
in that case please remember that all angles on top of a line (and then again below a line) must sum up to 180 degrees (this is what it takes to flip a "stick" on that line from left to right).
so, COD covers already 90 degrees of these 180.
that means AOD + BOC = 180 - 90 = 90 degrees.
now we know that the 2 angles are in the ratio of 1:5.
that means that BOC is 5 times as large as AOD.
and we can be more direct :
since the 2 angles are in the ratio 1:5 we are actually splitting the remaining 90 degrees into 6 parts (5+1).
and BOC gets then 5 of these 6 parts, and AOD gets the remaining 1 part.
so,
90/6 = 15
therefore, one of these parts is 15 degrees.
so, we know AOD = 15 degrees.
BOC = 5×15 = 75 degrees
or simply 90 - 15 = 75 degrees
I think the answer is C.50 miles
