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Kipish [7]
2 years ago
11

Twice the sum of a number and 2 is equal to three times the difference of the number and 7 Find the number.

Mathematics
1 answer:
romanna [79]2 years ago
4 0

Answer:

X=13

Step-by-step explanation:

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50 POINTS for both questions
love history [14]

Answer:

3. i think 15.5

4. 140*

Step-by-step explanation:

in number 4, d is a vertical angle to the angle measured at 140.

in number 3, QV=SV, so 17=4x-1     18=4x    18/4=x   x=4.5

and TS=TQ, so 3(x) + 2 = 3(4.5) + 2 = 13.5 + 2 = 15.5 =TQ

6 0
3 years ago
Read 2 more answers
Solve 5n + 6 = -3n - 10
Verizon [17]

Hi there! :)

Answer:

\huge\boxed{n = -2}

5n + 6 = -3n - 10

Solve for n:

Add 3n to both sides:

5n + 3n + 6 = -3n + 3n - 10

8n + 6 = -10

Subtract 6 from both sides:

8n + 6 - 6 = -10 - 6

8n = -16

Divide both sides by 8:

8n/8 = -16/8

n = -2.

3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7B%20%5Csqrt%7BR%20%7B%7D%5E%7B2%7D%20%2B%20W%20%7B%7D%5E%7B2%7D%20L%
AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

7 0
3 years ago
What is the domain of y = cot x?
aleksandrvk [35]

c had the same ? then got it right

4 0
3 years ago
Read 2 more answers
Helpppppppppp with this question???
irakobra [83]
Pretty sure it’s the second one
3 0
3 years ago
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