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Novay_Z [31]
3 years ago
12

Determine the slope and y-intercept of the line: y=-4x

Mathematics
1 answer:
lapo4ka [179]3 years ago
7 0
Equation y=-4x
m=-4. Slope is -4 y-intercept is 0

y-12=2(x-1)
y-12=2x-2
y=2x-2+12
y=2x+10
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Determine whether the given value is a statistic or a parameter. A homeowner measured the voltage supplied to his home on a rand
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5 but its probaly not right bc im just looking for pointsStep-by-step explanation:

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3 years ago
Find the value of x and y
Yakvenalex [24]

Answer:

x = 80, y = 122

Step-by-step explanation:

I got this equation by using vertical angles to create a complimentary angle pair (they sum to 90 degrees).

3/4x+2/5x-2=90°,

23/20x - 2=90°,

23/20x = 92°,

92/(23/20)

20/(1/4)

20(4)

= 80.

Since the angles are a linear pair on the left side(they sum to 180 degrees). Just subtract 180 from 3/4x-2 and substitute x into the expression.

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7 0
3 years ago
Read 2 more answers
How many nickels are there in seventeen dollars?
Hunter-Best [27]
20 nickels = 1 dollar

So, do 20 x 17.

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The answer is 340 nickels!
4 0
3 years ago
Number 10 !! I NEED HELP THANKYOU
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7 0
3 years ago
A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exa
yarga [219]

Answer:

z= \frac{85-70}{10}=1.5

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

Step-by-step explanation:

Assuming this complete question:

A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exams were scored on different scales. Remembering what he learned about the advantages of Z scores, he asks his friend for the mean and standard deviation of her class on the exam, as well as her final exam score. Here is the information:

Our student: Final exam score = 85; Class: M = 70; SD = 10.

His friend: Final exam score = 45; Class: M = 35; SD = 5.

The Z score for the student and his friend are:

A) Our student, Z= -1.07; his friend, Z= -1.14.

B) Our student, Z= 1.50; his friend, Z=2.00.

C) Our student, Z= 1.07; his friend, Z= -1.14.

D) Our student, Z= 1.07; his friend, Z= 1.50

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution

Let X the random variable that represent the scores for our student, and for this case we know that:

E(X)= \mu =70, SD_X=\sigma=10  

The z score is given by:

z=\frac{x-\mu}{\sigma}

If we use this we got:

z= \frac{85-70}{10}=1.5

Let Y the random variable that represent the scores for his friend, and for this case we know that:

E(Y)= \mu =35, SD_Y=\sigma=5  

The z score is given by:

z=\frac{y-\mu}{\sigma}

If we use this we got:

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

3 0
3 years ago
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