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nadya68 [22]
3 years ago
11

Write the point from of the equation for a line that passes through (6,—1) with a slope of 2

Mathematics
2 answers:
Paraphin [41]3 years ago
7 0

Answer:

y = 2x-13

Step-by-step explanation:

The equation for a line is

y = mx+b where m is the slope and b is the y intercept

y = 2x+b

We know a point so we have a y and an x, so we can solve for b

-1 = 2(6) +b

-1 =12+b

Subtract 12 from each side

-1-12 = 12-12+b

-13 =b

Substitute this into y = 2x+b

y = 2x-13

puteri [66]3 years ago
5 0

The equation for point-slope form is: y - y1 = m( x - x1)

We already know from what is given in the question that:

The value of x1 is: 6

And the value of y1 is: 1

Now all you have to do is plug it in:

y - (-1) = 2[x – (6)]

And then simplify:

y + 1 = 2( x - 6)

I hope this helps! :)

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Step-by-step explanation:

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3 years ago
Please, I need it ASAP!!!! I will give brainliest if correct!!!
LenKa [72]

Answer:

recursive: f(0) = 7; f(n) = f(n-1) -8

explicit: f(n) = 7 -8n

Step-by-step explanation:

The sequence is an arithmetic sequence with first term 7 and common difference -8. Since you're numbering the terms starting with n=0, the generic case will be ...

recursive: f(0) = first term; f(n) = f(n-1) + common difference

explicit: f(n) = first term + n·(common difference)

To get the answer above, fill in the first term and common difference values.

4 0
3 years ago
Hurry show your work
Nikolay [14]

Answer: \huge\boxed{\boxed{15}}

Step-by-step explanation:

<u>Given expression</u>

\large\boxed{\frac{12[30 - (9+4^2)]}{|10|-|-6| } }

<u>Simplify the exponents</u>

\large\boxed{=\frac{12[30 - (9+16)]}{|10|-|-6| } }

Simplify values in the parenthesis

\large\boxed{=\frac{12[30 - 25]}{|10|-|-6| } }

\large\boxed{=\frac{12[5]}{|10|-|-6| } }

<u>Simplify absolute values (all positive)</u>

\large\boxed{=\frac{12[5]}{10-6 } }

\large\boxed{=\frac{12[5]}{4 } }

<u>Simplify by division</u>

\large\boxed{=3~[5]}

<u>Simplify by multiplication</u>

\huge\boxed{\boxed{=15}}

Hope this helps!! :)

Please let me know if you have any questions

7 0
1 year ago
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