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2x - 2y + 5z - 2x - y + 3z
The first thing you need to do is to put all the common terms together.
2x - 2x - 2y - y + 5z + 3z
2x - 2x = 0 or nothing so we don't need to put that in the solution
-3y + 8z
The correct option is D
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Answer: There are 8 3/4 in 6
You can use a rule of three:
If in 3/4 there is 1 (3/4), How many 3/4 are in 6?:
3/4 → 1
6 → x
x=(6)(1)/(3/4)→
x=6/(3/4)→
x=(6/1)/(3/4)→
x=(6/1)(4/3)→
x=(6)(4)/[(1)(3)]→
x=24/3→
x=8
Answer: There are 8 3/4 in 6
11-19m=-16m-16
move -16m to the other side
sign changes from -16m to +16m
11-19m+16m =-16m+16m-16 ( combine like terms)
11-19m+16m=-16
11-3m=-16
move 11 to the other side
sign changes from +11 to -11
11-11-3m=-16-11
-3m=-16-11
-3m=-27
divide both sides by -3 to get +m and by itself
-3m/-3=-27/-3
m=9
Check solution by using substitution method
11-19m=-16m-16
11-19(9)=-16(9)-16
11-171=-144-16
-160=-160
Answer:
m=9
The | | sign is called a modulus, it means transform any number inside it to positive, so for example |-2| = 2 but |1| = 1.
therefore, -13 + |-7/4| = -13 + 7/4 = -52/4 + 7/4 = -45/4