Write the point from of the equation for a line that passes through (6,—1) with a slope of 2
2 answers:
Answer:
y = 2x-13
Step-by-step explanation:
The equation for a line is
y = mx+b where m is the slope and b is the y intercept
y = 2x+b
We know a point so we have a y and an x, so we can solve for b
-1 = 2(6) +b
-1 =12+b
Subtract 12 from each side
-1-12 = 12-12+b
-13 =b
Substitute this into y = 2x+b
y = 2x-13
The equation for point-slope form is: y - y1 = m( x - x1)
We already know from what is given in the question that:
The value of x1 is: 6
And the value of y1 is: 1
Now all you have to do is plug it in:
y - (-1) = 2[x – (6)]
And then simplify:
y + 1 = 2( x - 6)
I hope this helps! :)
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