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2 years ago

fiona has to plot a histogram of the given data , what frequency table should she use for the histogram?

Mathematics

1 answer:

fomenos2 years ago

3 0

Fiona is not very smart so should know herself what frequency table she should use for her histogram

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What is the average rate of change for this exponential function for the interval from x=2 to x=4?

mario62 [17]

The equation to calculate the average rate of change is: y/x

y = f(x2) - f(x1)x = x2 - x1

x1: 1 (The smaller x value. It can be any number)x2: 2 (The larger x value. It also can be any number)f(x1): The value when you plug x1 into the function.f(x2): The value when you plug x2 into the function.

If we know this, the variables for this problem are assuming the function is 10(5.5)^x:

x2: 2x1: 1f(x2): 10(5.5)^(2) = 302.5f(x1): 10(5.5)^(1)= 55

This means:y = 302.5 - 55 = 247.5x = 2 - 1 = 1

Remember: the equation for avg rate of change is y/x

So, our average rate of change for the function on the interval [1,2] is 247.5 (y/x = 247.5/1)

5 0

3 years ago

Read 2 more answers

12x5 – 10x2 + x – 45

qaws [65]

(a)
$12x ^{5} - 10x ^{2} + x - 45$
(b)we have 4 terms in this expression.
(c)+12 is the leading coefficient in
$12x ^{5}$

(d) constant is -45

6 0

3 years ago

Solve: The quantity 2 x minus 20 divided by 3 = 2x −5 −3 2 13

harina [27]

(2x-20)/3 = 2x start by multiplying both sides by 3

8 0

3 years ago

Calculate the Difference Quotient for f(x)=2x^2-3

Dafna11 [192]

Answer:

Calculate the Difference Quotient for f(x)=2x^2-3

Find f(x+h) and f(x), and plug these values into the difference quotient formula.

7 0

3 years ago

Find the area of the shaded region.

lbvjy [14]

Answer:

$48\pi\\\approx 150.796$

Step-by-step explanation:

1.Approach

To solve this problem, find the area of the larger circle, and the area of the smaller circle. Then subtract the area of the smaller circle from the larger circle to find the area of the shaded region.

2.Find the area of the larger circle

The formula to find the area of a circle is the following,

$A=(\pi)(r^2)$

Where (r) is the radius, the distance from the center of the circle to the circumference, the outer edge of the circle. ( $\pi$ ) represents the numerical constant (3.1415...). One is given that the radius of (8), substitute this into the formula and solve for the area,

$A_l=(\pi)(r^2)\\A_l=(\pi)(8^2)\\A_l=(\pi)(64)$

3.Find the area of the smaller circle

To find the area of the smaller circle, one must use a very similar technique. One is given the diameter, the distance from one end to the opposite end of a circle. Divide this by two to find the radius of the circle.

8 ÷2 = 4

Radius = 4

Substitute into the formula,

$A_s=(\pi)(r^2)\\A_s=(\pi)(4^2)\\A_s=(\pi)(16)$

4.Find the area of the shaded region

Subtract the area of the smaller circle from the area of the larger circle.

$A_l-A_s\\=64\pi - 16\pi\\=48\pi$

$\approx150.796$

5 0

2 years ago