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3 years ago

I need help fast !!!!

Mathematics

1 answer:

Westkost [7]3 years ago

7 0

The book is asking if 14/20 is the same as 16/24. In other words, we want to see if 14/20 = 16/24 is a true equation or not.

Let's find out

14/20 = 16/24
14*24 = 20*16 ... cross multiply
336 = 320

Since the last equation shown above is NOT true, this makes the first equation NOT true.

The equation 14/20 = 16/24 is false so they did NOT make a proportional number of shots

An alternative route is to convert each fraction to decimal form
14/20 = 0.7
16/24 = 0.6666... (the 6's go on forever)
We get two different decimal values so this confirms our answer

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The savings account offering which of these APRs and compounding periods offers the best APY?

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$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\
$

$\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\
$

$\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1$

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2 years ago

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vesna_86 [32]

6.2n-3.7n=85+45
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The answer is B. Hope this helps!

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3 years ago

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Answer:

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Answer:

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Hope this helps,

Adrian

Step-by-step explanation:

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