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Kipish [7]
4 years ago
12

What’s the approximate distance?

Mathematics
1 answer:
Lunna [17]4 years ago
8 0
Let m be the slope of the parallel lines, each having a slope of m
Then the distance between the parallel lines 
= (difference in y-intercept)/sqrt(1+m^2)

For the given problem,
difference in y-intercept = 4-2=2
slope = m = -1
Distance between lines = 2/sqrt(1+(-1)^2) =2/sqrt(2)=sqrt(2)=1.41421

Answer: distance between the parallel lines = 1.41 (to the nearest hundredth)
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Answer:

u = 4

v = 18

Step-by-step explanation:

in a parallelogram, diagonals bisect each other into two equal segments so we can do the following:

2u+2 = 5u-10

subtract '2u' from each side to get:

2 = 3u-10

add 10 to each side to get:

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Answer:

The answer to your question is the letter A) x ≥ 0.5

Step-by-step explanation:

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                           2(4x - 3) ≥ -3(3x) + 5x

Process

1.- Expand

                            8x - 6 ≥  - 9x + 5x

2.- Simplify

                            8x - 6 ≥ - 4x

3.- Add 6 units in both sides

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4.- Simplify

                                8x ≥ -4x + 6

5.- Add 4x in both sides

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6.- Simplify

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7.- Divide by 12 both sides

                                12x/12 ≥ 6/12

8.- Simplify

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