To find the Radius of a circle follow the formula-
r = <span>√A/pi
r = </span><span>√113/pi
r = 6
understand?</span>
1: always rearrange the equation to y = mx + c so....
x - y = o
x = y
So the gradient is 1 and it intersects the y axis at (0,0)
The three points could be (1,1), (2,2), (3,3) and so on
2: -x -2y = -10
Multiply everything by -1
x + 2y = 10
2y = 10 - x
y = 5 - x/2
The y intercept is 5 so you could use the point (0,5), (2,4), (4,3) and so on
3: x + y = -2
y = -2 - x
The y intercept is -2 so you could use the points (0,-2), (2,-4), (3,-5) and so on
4: -3y =-x -7
Multiply everything by -1
3y = x + 7
y = x/3 + 7/3
The y intercept is 7/3 so you could use the points (0,7/3), (3,10/3), (6,13/3) and so o
5: -y = -x + 1
y = x - 1
The y intercept is -1 so you could use the points (0,-1), (2,1), (3,2) and so on
Hope this helps! Any questions let me know :)
Answer:
Step-by-step explanation:
For a
2 + x = 15
x = 15 -2
x = 13
For B
x - 12 = 14
x = 12 + 14
x = 26
For C
3x = 12
x = 12/3
x = 4
Hope it helps:)
Answer:
B
Step-by-step explanation:
If you start to ask after 10:00 am, a lot of people isn't drinking caffeine. And, were trying to figure out the average.
Answer:
1
Step-by-step explanation:
The quadratic function
y = -2(x + 2)² - 1
has no real zeros because its vertex is located at (-2, -1) and it opens downward (the leading coefficient, -2, is negative)
A quadratic function has one real root if its vertex has the form (x, 0). If we add 1 to our equation, we get:
y = -2(x + 2)² - 1 + 1 = -2(x + 2)²
which has point (-2, 0) as vertex
