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77julia77 [94]
3 years ago
10

Plz show work 3x-5=1/2x+2x

Mathematics
1 answer:
Troyanec [42]3 years ago
8 0
3x - 5 = 1/2x + 2x 3x - 5 = .5x + 2x3x - 5 = 2.5x-3x     = -3x   -5= -.5x   divide by -.5 on both sidesx = 10
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Felix has a bucket of golf balls. The table shows the number of golf balls of each color in the bucket.
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3 years ago
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a tank is 3/7 full of water.After removing 420 litres it became 12/35 full .how much can the tank hold when full? ​
insens350 [35]

Answer:

4900 Litres

Step-by-step explanation:

First we need a common demoninator:

3/7=15/35

Then we subtract the two to figure out how much 420 Litres is:

15/35-12/35=3/35

3/35=420 litres

Divide amount by the numerater for thow much 1/x is.

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and multiply by the denomenator to get a full number on your fraction, and therefore a full tank.

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1 year ago
The Smith family went out to eat at Applebees. The total for their meal was $58.25. If they want to leave a 20%, how much tip sh
Len [333]

Answer:

$11.65

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20% of 58.25, "of" in math means multiplication. So you multiply it.

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.20 * 58.25

So your answer is, $11.65.

To find the total of the bill including the tip it would just be

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4 0
3 years ago
The two triangles shown below are simiar. Which statement is true of the transformation from ABC to A' B' C'
AfilCa [17]

Answer: Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .

Step-by-step explanation:

Since the triangles are similar, the ratio of their sides are equal.

And we can count the number of blocks over which AC and A'C' is drawn and take them to be their length,

Therefore,

AC = 16

A'C'= 8

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tanA = \frac{10}{4}

tanA'=\frac{5}{2}

which means tanA= tanA'

The angles do not change.

Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .

8 0
3 years ago
Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
Nana76 [90]

Answer:

(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2

Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

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(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

7 0
3 years ago
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